Problem 4. A trapezoidal channel with a bottom width B = 45 ft, a Manning's n = 0.018and side slopes of m = 1.5 has a maximum allowable depth of 4.5 ft. Calculate the maximumflow rate when the slope is 0.00025.

From the question, we can identify the following parameters:Bottom width (B) = 45 feetManning's n =…

Answered: Problem 4. A trapezoidal channel with a…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q. Determine the depth in a trapezoidal channel with side slopes of 1 to 1.5, a bottom width of 8 m and a channel slope of 0.0009. The discharge is 56 m /s and n = 0.017. 8m
Situation 9: A trapezoidal channel has a bottom width of 6 m and side slopes of 2 horizontal to 1 vertical. If the depth of flow is 1.2 m and the flow is 20.40 m^3/s. What is its hydraulic radius? a. 0.8868m b. 1.0955m c. 1.4223m d. 0.7864m Compute the slope of the channel for n = 0.014. a. 0.00023 b. 0.00094 c. 0.00081 d. 0.00047
A wide rectangular channel laid on a slope of 0.009 has a Manning's roughness coefficient n = 0.014. Determine the discharge for a normal depth of 2.0 m.
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A trapezoidal channel having a bottom slope of 0.001 is carrying a flow of 30 m³/s. The bottom width is 10.0 m and the side slopes are 2H to 1V. A control structure is built at the downstream end which raises the water depth at the downstream end to 5.0 m. Compute the water surface profile till 1.20 m. Manning n is 0.013 and a = 1. Select an appropriate Ay for your calculations.
(1-2) A trapezoidal channel has a bottom width of 6.0m, side slopes of 2 vertical: 4 horizontal, and carries a flow of 17m/s. Manning's roughness coefficient n can be taken as 0.02. The channel bed slope drops 2m per 1km. a) Calculate the normal water depth. b) Determine the critical depth. c) Calculate the corresponding critical slope.
4: A discharge of 25 cumec occurs in a rectangular open channel 2.7m wide with bed slope of 0.003 and roughness, n=0.014. If the channel ends in a free outfall, calculate the depth at the brink, yn and critical depth, yc. Determine the shape of the water-surface profile for a distance of 120m upstream from the brink. Note: use a 0.10m water depth interval in the channel. Y1 = ? L=? Y2=? L=? Y3=? L=? Yc= ?
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The base of the artificial channel has a bottom width of 3m and sides with a slope of 1 vertical to 2 horizontal. The depth of water being predicted/estimated is 1.2m when the discharge is 3.51m3/s. Using Manning's equation with n = 0.022 a. Calculate the slope of the channel bed.b. Calculate the discharge in m3/s when the depth of flow is 1.3m.
Q 1. Design an earthen channel which has a trapezoidal cross section with a bed width equal to 10 meters and side slopes equal to 2. It carries a discharge of 26.2 cumecs and has a Manning's roughness coefficient equal to 0.022. The maximum allowable flow velocity in the canal is given by: Vm/s of the canal and the flow depth. 0.6 do.64. Determine the maximum practical longitudinal slope meters ·
2. An unsymmetrical trapezoidal channel with one side inclined from horizontal by 35° and the other inclined from vertical by 40° is to be designed to carry a 2.0 cubic meters per second discharge. Determine the dimensions of the channel for most efficient section if roughness coefficient is 0.030 and average longitudinal slope is 0.05. Draw the cross section of the open channel considering the freeboard height. Use Chezy and Kutter's C formula.
Calculate the depth d in which the discharge (Q = 1.5 m / sec) will flow through the channel with trapezoid - shaped cross section. Width of the channel bed is (b = 2 m), slope of bed (S = 0.05%), sides slope is (Z = 1.5). The channel is excavated in gravel sends in which the roughness coefficient is (n = 0.0247).

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Problem 4. A trapezoidal channel with a bottom width B = 45 ft, a Manning's n = 0.018 and side slopes of m = 1.5 has a maximum allowable depth of 4.5 ft. Calculate the maximum flow rate when the slope is 0.00025.