Problem 4 Suppose a data stream is { 1 0 1 1 0 0 1 00011001101100 }, which will be interleaved by a block interleaver as below. What is the output of the interleaver?
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A: SUMMARY: - Hence, we discussed all the points.
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- QUESTION 5 Suppose str is declared as an array of bytes, and contains a null-terminated string. Write the assembly code to count the number of characters in the string (not including the null character), and leave the count value in the RAX register. For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BI U S I x? X2 Paragraph Arial 10pt A PWrite a short C program that declares and initializes (to any value you like) a double, an int, and a char. Next declare and initialize a pointer to each of the three variables. Your program should then print the address of, and value stored in, and the memory size (in bytes) of each of the six variables.Using C Language In this function, b has the address of a memory buffer that is num_bytes long. The function should repeatedly copy the 16 byte pattern that pattern16 points at into the memory buffer until num_bytes have been written. If num_bytes is not a multple of 16, the final write of the 16 byte pattern should be truncated to finish filling the buffer. void memset16(void *b, int num_bytes, void *pattern16) For example if the 16 bytes that pattern16 points at is 00 11 22 33 44 55 66 77 88 99 aa bb cc dd ee ff, then memset(b, 20, pattern16) should write to the buffer pointed at by p the 20 bytes 00 11 22 33 44 55 66 77 88 99 aa bb cc dd ee ff 00 11 22 33. Use SSE instructions to improve efficiency. Here's pseudocode. x = SSE unaligned load from pattern16while (num_bytes >= 16) SSE unaligned store x to p advance p by 16 bytes decrement num_bytes by 16while (num_bytes > 0) store 1 byte from pattern16 to p advance p by 1 byte advance pattern16 by 1 byte…
- The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.#include <stdio.h>int main( ){ char c = 'Z'; char *cp = &c; printf("cp is %p\n", cp); printf("The character at cp is…Consider two integer arrays B and D of 100 elements. Let X2 and X3 contain the base address of array "B" and "D", respectively, and the index į is in X0, h is in X10. Write LEGV8 code to perform the following operations: (a) Get B[15] from memory and put it in register X5. (b) Put the value 132 in D[6]. (c) Translate the following C code into LEGv8 instructions int j = 50, h; do { D[2*j] = (B[j] + B[j+2])*9 - h; j^j -2; while {j >0}; DO NOT use multiply instruction in your code, use shift instruction for multiplication instead! (d)How many instructions are executed during the running of the code in (c), and how many memory data references are made during executio'n?Explain in details what the following are used for : (a) Lambda (b) Intermediate stream operations (c)Terminal stream Operation.