Problem 4 Press-Fit (3-116) Matlab Code is for (3-117) The table gives data concerning the shrink fit of two cylinders of differing materials and dimensional specification in inches. Elastic constants for different materials may be found in Table A-5. Identify the radial interference 8, then find the interference pressure p, and the tangential normal stress on both sides of the fit surface. If dimensional tolerances are given at fit surfaces, repeat the problem for the highest and lowest stress levels. Problem Number 3-116 3-117 Inner Cylinder Material d; 0 0 Steel Steel do 2.002 2.002 Outer Cylinder D; Material Steel Cast iron 2.000 2.000 Do 3.00 3.00

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Problem 4 Press-Fit (3-116) Matlab Code is for (3-117)
The table gives data concerning the shrink fit of two cylinders of differing materials and
dimensional specification in inches. Elastic constants for different materials may be found in
Table A-5. Identify the radial interference &, then find the interference pressure p, and the
tangential normal stress on both sides of the fit surface. If dimensional tolerances are given at
fit surfaces, repeat the problem for the highest and lowest stress levels.
Problem
Number Material
3-116
3-117
Inner Cylinder
di
Steel
Steel
0
0
do
2.002
2.002
Outer Cylinder
D;
Material
Steel
Cast iron
2.000
2.000
Do
3.00
3.00
Transcribed Image Text:Problem 4 Press-Fit (3-116) Matlab Code is for (3-117) The table gives data concerning the shrink fit of two cylinders of differing materials and dimensional specification in inches. Elastic constants for different materials may be found in Table A-5. Identify the radial interference &, then find the interference pressure p, and the tangential normal stress on both sides of the fit surface. If dimensional tolerances are given at fit surfaces, repeat the problem for the highest and lowest stress levels. Problem Number Material 3-116 3-117 Inner Cylinder di Steel Steel 0 0 do 2.002 2.002 Outer Cylinder D; Material Steel Cast iron 2.000 2.000 Do 3.00 3.00
>> %Press-Fit Example Problem 117
Steel, psi
ES=30*10^6
MUS=0.292;
Cast Iron
EC 14.5*10^6;
MuC=0.211;
di=0;
d0=2.002;
Di=2.000;
D0=3.000;
% tolerance
tol=d0-D0;
Pressure Eq. (3-56)
R=Di/2;
r0=D0/2;
ri=di/2;
Hub= (1/ES) * ((r0^2+R^2) / (r0^2-R^2)+Mus);
Inner= (1/EC) * ((R^2+ri^2) / (R^2-ri^2) -MuC);
p=tol/ (R* (Hub+Inner))
ES =
p =
30000000
-6.6174e+06
Transcribed Image Text:>> %Press-Fit Example Problem 117 Steel, psi ES=30*10^6 MUS=0.292; Cast Iron EC 14.5*10^6; MuC=0.211; di=0; d0=2.002; Di=2.000; D0=3.000; % tolerance tol=d0-D0; Pressure Eq. (3-56) R=Di/2; r0=D0/2; ri=di/2; Hub= (1/ES) * ((r0^2+R^2) / (r0^2-R^2)+Mus); Inner= (1/EC) * ((R^2+ri^2) / (R^2-ri^2) -MuC); p=tol/ (R* (Hub+Inner)) ES = p = 30000000 -6.6174e+06
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