Problem 4 (20 points) (Chap 7) (Learning objective: Magnetic field in a straight coil)A cardboard tube is 10 cm long and 5 mm in diameter, with air inside ("air core").100 windings of insulated wire are wound onto the tube, and connected to a 2 A currentsource. Also, 300 windings of insulated wire wound onto the same tube but in the oppositedirection, and connected to a 4 A current source. The two sets of windings are overlapping,but they do not short out because they are insulated. What is the magnitude of the magneticflux density in the coil?

Here is the step-by-step explanation:Given:Length of the coil (L) = 10 cm = 0.1 mDiameter of the…

Answered: Problem 4 (20 points) (Chap 7)…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm², and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (ur = 800 for iron).
An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm2, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (4, = 800 for iron).
(a) A magnetic circuit with the specified dimensions is as shown in Figure 1 on page 2. The center limb has a winding of 500 turns and there are air gaps in the left and right limbs as shown. The mean lengths of the various magnetic sections are l = 100 cm, l2 = 79.85 cm, l3 = 120 cm and lg = 1.5 mm. The center limb has a cross-sectional area of 32 cm? and each of the side limbs has a cross-sectional area of 16 cm². The magnetization curve for the material is given by the following: 1. %3D H (At/m) 100 220 260 300 320 B (T) 0.1 0.2 0.25 0.3 0.35 (i) Let p. be the flux in the center limb and p, be the flux in the air gaps. Using the magnetic equivalent circuit of Figur exciting current I required to produce a flux of 0.4 mWb in each air gap. You may neglect leakage and fringing in your calculations. The permeability of free space u, is 47 x 10- H/m. 1, determine the (ii) Determine the energy stored in the air gaps and in the core, respectively. 12 13 Figure 1
Question 1 A ferromagnetic core with a relative permeability of 1500 is shown in Figure 2. The dimensions are as shown in the diagram, and the depth of the core is 7 cm. The air gaps on the left and right sides of the core are 0.070 and 0.020 cm, respectively. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 400 turns in the coil wrapped around the center leg of the core and if the current in the coil is 1.0 A, what is a) the flux in each of the left, center, and right legs of the core? b) the flux density in each air gap? 7 cm ст ст 30 cm 30 cm 7 cm 400 turns 0.05 cm 30 cm 0.07 cm 7 cm Core depth = 7 cm Figure 2
An iron circuit with a small0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm2, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (u, = 800 for iron). Figure 1
Please answer a, b, c and d
3- A magnetic core with an air gap is shown in below Figure. The depth of the core is 3 cm, the length of the air gap in the core is 4 cm, and the number of turns on the coil is 100. How much current is required to produce total flux of 0.00052 Weber? (H= 2000, Ho=4.n107). 6 cm 20 cm N = 100 4 cm = lg 6 cm 6 cm 18 cm 12 cm 18 cm 6 ст Depth = 3 cm
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A magnetic circuit has 150 turns-coil, the cross- sectional area 5 x 10-4 m2 and the length of the magnetic circuit 25 x 10-2 m. What are the values of magnetic field intensity and relatíve permeability when the current is 2 A and total flux is 0.3 x 10-3 Wb? (a) 1200 AT/m and 397.9 (b) 300 AT/m and 500 x 10-6 (c) 300 AT/m and 397.9 (d) 1200 AT/m and 500 x 10-6
A solenoid is 1 Cm long with a diameter of 0.5 Cm. The core is SiFe with a relative permeability of 4200. Assuming a current of 100 mA, what is the maximum number of turns for the winding that keeps the core under the saturation magnetic field of about 1.5 Tesla?
Consider a coil as Figure 10 turns, placed in a magnetic field B= (100 x2 cos 103t) az T and R=10000 Determine the current in the circuit. The units of length are in m R -0.1 + Vemf 0.1 -0.1 B 0.1
A rectangular coil of wire has a length of 3 cm and a width of 4 cm. It is in a 0.004 T magnetic field. What is the magnetic flux through the coil if the face of the coil is parallel to the B-field lines? What is the flux if the angle between the face of the coil and the magnetic field is 75°?

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