Problem 31.4 A continuous random variable has a pdf 1-즉 0

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### Problem 31.4

A continuous random variable has a probability density function (pdf) given by:

\[
f(x) = 
\begin{cases} 
1 - \frac{x}{2} & \text{if } 0 < x < 2 \\
0 & \text{otherwise}
\end{cases}
\]

Find the expected value and the variance.

#### Explanation:

- **Probability Density Function (pdf):**
  - For the interval \(0 < x < 2\), the function \(f(x) = 1 - \frac{x}{2}\) defines the likelihood of the random variable taking a value within this range.
  - Outside this range, the pdf is zero, indicating that the random variable cannot take values outside of \((0, 2)\).

- **Objective:**
  - Calculate the **expected value (mean)** and **variance** of the given probability density function.

To solve, one would typically:

1. **Find the Expected Value (E[X]):**
   - Use the integral of \(x \cdot f(x)\) over the interval from 0 to 2.

2. **Find the Variance (\(\text{Var}(X)\)):**
   - Use the formula \(\text{Var}(X) = E[X^2] - (E[X])^2\), where \(E[X^2]\) is the integral of \(x^2 \cdot f(x)\) over the same interval.
Transcribed Image Text:### Problem 31.4 A continuous random variable has a probability density function (pdf) given by: \[ f(x) = \begin{cases} 1 - \frac{x}{2} & \text{if } 0 < x < 2 \\ 0 & \text{otherwise} \end{cases} \] Find the expected value and the variance. #### Explanation: - **Probability Density Function (pdf):** - For the interval \(0 < x < 2\), the function \(f(x) = 1 - \frac{x}{2}\) defines the likelihood of the random variable taking a value within this range. - Outside this range, the pdf is zero, indicating that the random variable cannot take values outside of \((0, 2)\). - **Objective:** - Calculate the **expected value (mean)** and **variance** of the given probability density function. To solve, one would typically: 1. **Find the Expected Value (E[X]):** - Use the integral of \(x \cdot f(x)\) over the interval from 0 to 2. 2. **Find the Variance (\(\text{Var}(X)\)):** - Use the formula \(\text{Var}(X) = E[X^2] - (E[X])^2\), where \(E[X^2]\) is the integral of \(x^2 \cdot f(x)\) over the same interval.
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