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Problem 3) -TA (mol/dm³ s): . T(K): 0.012 300 A + 2B→ 3C mol dm³ XA = 4.00 0.064 327 , XB = 6.00 0.96 354 mol dm³ 11.66 380 From the data, find the following: (A) The activation energy in J/mol and he frequency factor (the pre-exponential factor), which will have the same units as the rate constant k. You will need to calculate the "k" values first before creating the Arrhenius plot.

Problem 3) -TA (mol/dm³ s): . T(K): 0.012 300 A + 2B→ 3C mol dm³ XA = 4.00 0.064 327 , XB = 6.00 0.96 354 mol dm³ 11.66 380 From the data, find the following: (A) The activation energy in J/mol and he frequency factor (the pre-exponential factor), which will have the same units as the rate constant k. You will need to calculate the "k" values first before creating the Arrhenius plot.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Problem 3) -TA (mol/dm³ s): 0.012 . T (K): 300 ХА = A + 2B → 3C mol Хв dm3, XB = 6.00- dm³ 4.00 0.064 327 0.96 354 mol dm³ 11.66 380 From the data, find the following: (A) The activation energy in J/mol and he frequency factor (the pre-exponential factor), which will have the same units as the rate constant k. You will need to calculate the "k" values first before creating the Arrhenius plot.
Transcribed Image Text:Problem 3) -TA (mol/dm³ s): 0.012 . T (K): 300 ХА = A + 2B → 3C mol Хв dm3, XB = 6.00- dm³ 4.00 0.064 327 0.96 354 mol dm³ 11.66 380 From the data, find the following: (A) The activation energy in J/mol and he frequency factor (the pre-exponential factor), which will have the same units as the rate constant k. You will need to calculate the "k" values first before creating the Arrhenius plot.
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