2. A system consisting of 3kg of air (R= 0.287 kJ/kgK), undergoes the polytropic changes shown in the PV diagram. Analyze the data and fill in the blanks in the table. k 1.4 1 2 3 1 P (kPa) 75 V (m³) 2 T(K) 465

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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2. A system consisting of 3kg of air (R= 0.287 kJ/kgK), undergoes the polytropic changes shown in the PV
diagram.
Analyze the data and fill in the blanks in the table.
P4
k
1.4
1
2
3
1
P (kPa)
75
V (m³)
2
T(K)
465
Note: In trajectory 1 to 2, we are given k=1.4 as data, therefore this trajectory is adiabatic, that is, T1 # T2
Use the polytropic process equation P1V1^k=P2V2^k to determine the unknown for path 1
Transcribed Image Text:2. A system consisting of 3kg of air (R= 0.287 kJ/kgK), undergoes the polytropic changes shown in the PV diagram. Analyze the data and fill in the blanks in the table. P4 k 1.4 1 2 3 1 P (kPa) 75 V (m³) 2 T(K) 465 Note: In trajectory 1 to 2, we are given k=1.4 as data, therefore this trajectory is adiabatic, that is, T1 # T2 Use the polytropic process equation P1V1^k=P2V2^k to determine the unknown for path 1
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