Problem 3: Control Volumes When a water jet strikes a stationary inclined plate, it breaks into two jets at 2 and 3 with equal velocity Vjet but unequal volumetric flow rates (aQ at 2 and (1 - a) Q at 3, where 0 ≤ a ≤ 1). The reason is that, for frictionless flow, a fluid cannot exert a tangential force on the plate (i.e., Ft = 0). (1) Find a as a function of the plate angle 0. (2) Find the magnitude of the force Fr required to hold the plate stationary for 0 = π/4, V₁ = 3 m/s, when the mass rate flowing out of the nozzle is of m = 0.5 kg/s. αρ, ν (2) P, Q, A, V Fn F₁ = 0 (1-α) Q, V Figure 3: Water jet hitting a stationary inclined plate.

Elements Of Electromagnetics
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Problem 3: Control Volumes
When a water jet strikes a stationary inclined plate, it breaks into two jets at 2 and 3 with equal
velocity Vjet but unequal volumetric flow rates (aQ at 2 and (1 - a) Q at 3, where 0 ≤ a ≤ 1). The
reason is that, for frictionless flow, a fluid cannot exert a tangential force on the plate (i.e., Ft = 0).
(1) Find a as a function of the plate angle 0.
(2) Find the magnitude of the force Fr required to hold the plate stationary for 0 = π/4, V₁ =
3 m/s, when the mass rate flowing out of the nozzle is of m = 0.5 kg/s.
αρ, ν
(2)
P, Q, A, V
Fn
F₁ = 0
(1-α) Q, V
Figure 3: Water jet hitting a stationary inclined plate.
Transcribed Image Text:Problem 3: Control Volumes When a water jet strikes a stationary inclined plate, it breaks into two jets at 2 and 3 with equal velocity Vjet but unequal volumetric flow rates (aQ at 2 and (1 - a) Q at 3, where 0 ≤ a ≤ 1). The reason is that, for frictionless flow, a fluid cannot exert a tangential force on the plate (i.e., Ft = 0). (1) Find a as a function of the plate angle 0. (2) Find the magnitude of the force Fr required to hold the plate stationary for 0 = π/4, V₁ = 3 m/s, when the mass rate flowing out of the nozzle is of m = 0.5 kg/s. αρ, ν (2) P, Q, A, V Fn F₁ = 0 (1-α) Q, V Figure 3: Water jet hitting a stationary inclined plate.
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