Problem 3: An I = 10 A current is charging a D = 1.0 cm diameter parallel-plate capacitor. What is the magnetic field strength at a point s = 2.0 mm radially from the center of the wire leading to the capacitor? What is the magnetic field strength at a point s = 2.0 mm radially from the center of the capacitor? dt a) Ampere-Maxwell law reads f B. ds = Holthrough +€0, where B-ds is the line integral of magnetic field along a closed loop, Ithrough is the current passing through the loop, and is the electric flux through the surface bounded by the loop. 00 In Fig 3, we place a loop of radius s = 2.0 mm around the current leading to the capacitor. The magnetic field created by the current is circumferential, and due to the symmetry of the problem it has the same value in each point of the loop, so f Bout ds = Bout f ds = 27sBout ('out' is for outside the capacitor). What is the current passing through the loop? The electric flux through this loop is equal to zero - can you explain why? Use this to compute the magnetic field strength at 2.0 mm from the center of the wire. Bout FIG. 3: The scheme for Problem 3a

Problem 3: An I = 10 A current is charging a D = 1.0 cm diameter parallel-plate capacitor. What is the magnetic field strength at a point s = 2.0 mm radially from the center of the wire leading to the capacitor? What is the magnetic field strength at a point s = 2.0 mm radially from the center of the capacitor? dt a) Ampere-Maxwell law reads f B. ds = Holthrough +€0, where B-ds is the line integral of magnetic field along a closed loop, Ithrough is the current passing through the loop, and is the electric flux through the surface bounded by the loop. 00 In Fig 3, we place a loop of radius s = 2.0 mm around the current leading to the capacitor. The magnetic field created by the current is circumferential, and due to the symmetry of the problem it has the same value in each point of the loop, so f Bout ds = Bout f ds = 27sBout ('out' is for outside the capacitor). What is the current passing through the loop? The electric flux through this loop is equal to zero - can you explain why? Use this to compute the magnetic field strength at 2.0 mm from the center of the wire. Bout FIG. 3: The scheme for Problem 3a

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter34: Maxwell’s Equations And Electromagnetic Waves

Section34.2: Generalized Form Of Faraday’s Law

Problem 34.2CE

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