Problem 3: An I = 10 A current is charging a D = 1.0 cm diameter parallel-plate capacitor. What is the magnetic field strength at a point s = 2.0 mm radially from the center of the wire leading to the capacitor? What is the magnetic field strength at a point s = 2.0 mm radially from the center of the capacitor? dt a) Ampere-Maxwell law reads f B. ds = Holthrough +€0, where B-ds is the line integral of magnetic field along a closed loop, Ithrough is the current passing through the loop, and is the electric flux through the surface bounded by the loop. 00 In Fig 3, we place a loop of radius s = 2.0 mm around the current leading to the capacitor. The magnetic field created by the current is circumferential, and due to the symmetry of the problem it has the same value in each point of the loop, so f Bout ds = Bout f ds = 27sBout ('out' is for outside the capacitor). What is the current passing through the loop? The electric flux through this loop is equal to zero - can you explain why? Use this to compute the magnetic field strength at 2.0 mm from the center of the wire. Bout FIG. 3: The scheme for Problem 3a
Problem 3: An I = 10 A current is charging a D = 1.0 cm diameter parallel-plate capacitor. What is the magnetic field strength at a point s = 2.0 mm radially from the center of the wire leading to the capacitor? What is the magnetic field strength at a point s = 2.0 mm radially from the center of the capacitor? dt a) Ampere-Maxwell law reads f B. ds = Holthrough +€0, where B-ds is the line integral of magnetic field along a closed loop, Ithrough is the current passing through the loop, and is the electric flux through the surface bounded by the loop. 00 In Fig 3, we place a loop of radius s = 2.0 mm around the current leading to the capacitor. The magnetic field created by the current is circumferential, and due to the symmetry of the problem it has the same value in each point of the loop, so f Bout ds = Bout f ds = 27sBout ('out' is for outside the capacitor). What is the current passing through the loop? The electric flux through this loop is equal to zero - can you explain why? Use this to compute the magnetic field strength at 2.0 mm from the center of the wire. Bout FIG. 3: The scheme for Problem 3a
College Physics
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Hello can you help me with part A because I don't know how to start it
Transcribed Image Text:Problem 3: An I = 10 A current is charging a D = 1.0 cm diameter parallel-plate capacitor. What is the
magnetic field strength at a point s = 2.0 mm radially from the center of the wire leading to the capacitor?
What is the magnetic field strength at a point s = 2.0 mm radially from the center of the capacitor?
a) Ampere-Maxwell law reads f B. ds = Holthrough + €0μ doe
B-ds is the line integral of magnetic field along a closed loop, Ithrough is
the current passing through the loop, and De is the electric flux through
the surface bounded by the loop.
where
000
In Fig 3, we place a loop of radius s = 2.0 mm around the current
leading to the capacitor. The magnetic field created by the current is
circumferential, and due to the symmetry of the problem it has the same
value in each point of the loop, so f Bout ds = Bout f ds = 2лBout ('out'
is for outside the capacitor). What is the current passing through the loop? The electric flux through this
loop is equal to zero - can you explain why? Use this to compute the magnetic field strength at 2.0 mm
from the center of the wire.
Bout
FIG. 3: The scheme for Problem 3a
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