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Problem 3: Amass is sliding on a frictionless surface with a speed v. It runs into a linear X spring with a spring constant of k, which compresses from position x; to position xf. X3B m ©theexpertta.com Write a general expression for the force that the spring exerts on the mass, in term of k and x. Choose the initial position of the front of the spring to be x=0. Fspring = -kx / Correct! Part (b) Select the equation that correctly describes the work done by the spring to stop the mass. OW= -kx? OW= - *k x dx + ½ m v- OW= - *k x dx Ow= *f k x dx OW= - Xfk x dx - , m v? OW = - * F x dx Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. Part (c) Evaluate the relationship in part (b) to arrive at an expression for the work done in terms of known variables. Part (d) Solve for the numerical value of the work done in Joules given that x; = 0, x = 68 cm, and k= 145 N/m. W =- 33.5 W = -33.5 / Correct!

Problem 3: Amass is sliding on a frictionless surface with a speed v. It runs into a linear X spring with a spring constant of k, which compresses from position x; to position xf. X3B m ©theexpertta.com Write a general expression for the force that the spring exerts on the mass, in term of k and x. Choose the initial position of the front of the spring to be x=0. Fspring = -kx / Correct! Part (b) Select the equation that correctly describes the work done by the spring to stop the mass. OW= -kx? OW= - *k x dx + ½ m v- OW= - *k x dx Ow= *f k x dx OW= - Xfk x dx - , m v? OW = - * F x dx Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. Part (c) Evaluate the relationship in part (b) to arrive at an expression for the work done in terms of known variables. Part (d) Solve for the numerical value of the work done in Joules given that x; = 0, x = 68 cm, and k= 145 N/m. W =- 33.5 W = -33.5 / Correct!

Physics for Scientists and Engineers: Foundations and Connections
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter5: Newton's Laws Of Motion
Section: Chapter Questions
Problem 68PQ
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Problem 3: Amass is sliding on a frictionless surface with a speed v. It runs into a linear spring with a spring constant of k, which compresses from position x; to position xp. m ©theexpertta.com Write a general expression for the force that the spring exerts on the mass, in term of k and x. Choose the initial position of the front of the spring to be x=0. Fspring =-kx / Correct! Part (b) Select the equation that correctly describes the work done by the spring to stop the mass. Ow=-kx? OW=- *fk x dx + , m v OW=-kx dx Ow= f *f k x dx OW= - *k x dx - , m v? OW = - * F x dx Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. Part (c) Evaluate the relationship in part (b) to arrive at an expression for the work done in terms of known variables. Part (d) Solve for the numerical value of the work done in Joules given that x; = 0, x = 68 cm, and k= 145 N/m. W = - 33.5 W = -33.5 / Correct!
Transcribed Image Text:Problem 3: Amass is sliding on a frictionless surface with a speed v. It runs into a linear spring with a spring constant of k, which compresses from position x; to position xp. m ©theexpertta.com Write a general expression for the force that the spring exerts on the mass, in term of k and x. Choose the initial position of the front of the spring to be x=0. Fspring =-kx / Correct! Part (b) Select the equation that correctly describes the work done by the spring to stop the mass. Ow=-kx? OW=- *fk x dx + , m v OW=-kx dx Ow= f *f k x dx OW= - *k x dx - , m v? OW = - * F x dx Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. Part (c) Evaluate the relationship in part (b) to arrive at an expression for the work done in terms of known variables. Part (d) Solve for the numerical value of the work done in Joules given that x; = 0, x = 68 cm, and k= 145 N/m. W = - 33.5 W = -33.5 / Correct!
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