228.92)È HE Hm₂m₂N/m SubmitNow, three masses m₁ = 3.5 kg, m₂ = 10.5 kg and m3 = 7 kg hang from three identical springs in a motionless elevator.The springs all have the same spring constant that you just calculated above.What is the force the top spring exerts on the top mass?N Submit3) What is the distance the lower spring is stretched from its equilibrium length?cm Submit4) Now the elevator is moving downward with a velocity of v = -2.7 m/s but accelerating upward with an acceleration ofa = 5.4 m/s². (Note: an upward acceleration when the elevator is moving down means the elevator is slowing down.)What is the force the bottom spring exerts on the bottom mass?N Submit5) What is the distance the upper spring is extended from its unstretched length?cm Submit

Dear student since you have asked multiple question ls, I am answering the first question as per the…

2) ÈËË ma Now, three masses m₁ = 3.5 kg, m₂ = 10.5 kg and m3 = 7 kg hang from three identical springs in a motionless elevator. The springs all have the same spring constant that you just calculated above. What is the force the top spring exerts on the top mass? N Submit

2) ÈËË ma Now, three masses m₁ = 3.5 kg, m₂ = 10.5 kg and m3 = 7 kg hang from three identical springs in a motionless elevator. The springs all have the same spring constant that you just calculated above. What is the force the top spring exerts on the top mass? N Submit

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A massless spring with spring constant 26 N/m hangs vertically. A body of mass 1.0 kg is attached to its free end and then released. Assume that the spring was unstretched before the body was released. Find how far below the initial position the body descends. I don't understand why I'm getting this first part wrong specifically because the formula is just x= mg/k because F=kx.
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A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass-spring system is disturbed from its rest state by the force F(t) = 80 cos(8t). The force F(t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds. a. Determine the spring constant k. k= 1000 Newtons / meter b. Formulate the initial value problem for y(t), where y(t) is the displacement of the object from its equilibrium rest state, measured positive in the downward direction. (Give your answer in terms of y, y' , y ", t.) Differential equation: 10y"+1000y=80cos(8t) help (equations) Initial conditions: y(0) = 0 and y'(0) help (numbers) c. Solve the initial value problem for y(t). y(t) = help (formulas) d. Plot the solution and determine the maximum excursion from equilibrium made by the object on the time interval 0
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14a
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