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A van accelerates down a hill (see figure below), going from rest to 30.0 m/s in 5.60 s. During the acceleration, a toy (m 0.190 kg) hangs by a string from the van's ceiling. The acceleration is such that the string remains perpendicular to the ceiling. (a) Determine the angle 8. 0 (b) Determine the tension in the string. N

A van accelerates down a hill (see figure below), going from rest to 30.0 m/s in 5.60 s. During the acceleration, a toy (m 0.190 kg) hangs by a string from the van's ceiling. The acceleration is such that the string remains perpendicular to the ceiling. (a) Determine the angle 8. 0 (b) Determine the tension in the string. N

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A van accelerates down a hill (see figure below), going from rest to 30.0 m/s in 5.60 s. During the acceleration, a toy (m = 0.190 kg) hangs by a string from the van's ceiling. The acceleration is such that the string remains perpendicular to the ceiling. A (a) Determine the angle 8. 0 (b) Determine the tension in the string. N
Transcribed Image Text:A van accelerates down a hill (see figure below), going from rest to 30.0 m/s in 5.60 s. During the acceleration, a toy (m = 0.190 kg) hangs by a string from the van's ceiling. The acceleration is such that the string remains perpendicular to the ceiling. A (a) Determine the angle 8. 0 (b) Determine the tension in the string. N
Expert Solution
Step 1: Determine the given values

The mass of the toy is,

m equals 0.190 space kg


The final speed of the car is,

v subscript f equals 30 space straight m divided by straight s


Time taken by a car is,

t equals 5.60 space straight s


The value of acceleration due to gravity is,

g equals 9.8 space straight m divided by straight s squared

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