Problem 2: You are developing a new gas exchange nozzle for scuba tanks that will be used indeep sea diving. The nozzles are rated to withstand pressures up to 12 atmospheres which isexperienced at a depth of 120.7 meters. Up to this point, 96% of your nozzles in previous testshave functioned flawlessly at that depth. In testing your current iteration, 6 of the 200 nozzlestested failed at that depth. Can you claim a statistically significant improvement over previoustests with a significance level of 0.05? Why or why not? Use critical rejection criteria, P-values,or confidence intervals. Document your full process.

The expected proportion of failures in the previous tests is given as 4% or 0.04 based on the…

Answered: Problem 2: You are developing a new gas…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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To illustrate the effects of driving under the influence (DUI) of alcohol, a police officer brought a DUI simulator to a local high school. Student reaction time in an emergency was measured with unimpaired vision and also while wearing a pair of special goggles to simulate the effects of alcohol on vision. For a random sample of nine teenagers, the time (in seconds) required to bring the vehicle to a stop from a speed of 60 miles per hour was recorded. Complete parts (a) and (b). Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers. Click the icon to view the data table. (a) Whether the student had unimpaired vision or wore goggles first was randomly selected. Why is this a good idea in designing the experiment? A. This is a good idea in designing the experiment because it controls for any "learning" that may occur in using the simulator. B. This is a good idea in designing the experiment because…
You are a researcher who wants to know what the mean (µ) level of anxiety would be for the whole population if they were all receiving a new anti-anxiety therapy. You can’t give the therapy to the whole population, so you give it to a sample, and you get M = 32.1 as the average anxiety level for the sample on the therapy. What is the reason that you can’t just simply assume that µ = 32.1? You didn’t use random assignment Sampling error Descriptive statistics Inferential statistics
An educational psychologist is examining response times to an on-screen stimulus. The researcher believes there might be a weak effect from age, but expects a more pronounced effect for different color contrasts. She decides to examine a black on white (B/W) combination compared to 2 alternatives: red on white (R/W) and yellow on blue (Y/B). Here is the data for response times (in milliseconds): B/W R/W Y/B 16–17 213025351592110 201931234320716 42023218442534 18–19 1433242512161720 3936173735154719 2836312336234531 20–21 2718273916212423 2926412920312719 3643173928264043 Using MS Excel, conduct a 2-way ANOVA with α=0.05α=0.05. Fill in the summary table. The last column in the table below is read as, "Partial Eta-squared " and is a concept that was NOT covered in the lectures. Partial ηη 2 is used when there is a chance the data is not independent (click here to read more if interested) Computing the values for "Partial ηη 2" is not…
FACTORS FOR I AND R CONTROL CHARTS Observations in Sample, n dz A2 dz D3 D4 2 1.128 1.880 0.853 3.267 3 1.693 1.023 0.888 2.574 4 2.059 0.729 0.880 2.282 5. 2.326 0.577 0.864 2.114 6. 7. 2.534 0.483 0.848 2.004 2.704 0.419 0.833 0.076 1.924 8. 2.847 0.373 0.820 0.136 1.864 2.970 0.337 0.808 0.184 1.816 10 3.078 0.308 0.797 0.223 1.777 11 3.173 0.285 0.787 0.256 1.744 12 13 3.258 3.336 3.407 0.266 0.249 0.235 0.778 0.770 0.763 0.283 1.717 0.307 1.693 1.672 1.653 14 0.328 15 3.472 0.223 0.756 0.347 3.532 0.212 0.750 0.744 0.739 0.363 0.378 0.391 16 1.637 17 18 3.588 0.203 1.622 3.640 0.194 1.608 19 20 3.689 3.735 0.187 0.734 0.403 1.597 0.180 0.729 0.415 1.585 21 22 3.778 3.819 1.575 1.566 0.173 0.724 0.425 0.434 0.167 0.720 23 24 25 3.858 3.895 3.931 0.162 0.157 0.153 0.716 0.712 1.557 1.548 0.443 0.451 0.708 0.459 1.541
Please review Section 11.1. Are you an impulse shopper? A survey of 800 grocery shoppers indicated that 36% of males and 42% of females make an impulse purchase every time they shop. Assume that the survey consisted of 400 males and 400 females. Let group 1 be the males and let group 2 be the females. a = 0.01 H, :T, = R, H :, # R, Calculate the test statistic: (Round to three decimal places as needed.) Determine the critical value: (Round to three decimal places as needed.) State the Conclusion: Please review Section 12.2. An agent for a residential real estate company in a suburb located outside a major city has the business objective of developing more accurate estimates of the monthly rental cost for apartments. Toward the goal, the agent would like to use the size of an apartment, as defined by square footage to predict the monthly rental cost. The agent selects a sample of 8 one-bedroom apartments and the data are shown. Size (Square Feet) Monthly Rent ($) 875 1550 850 1350 950…
NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6 Step 1 of 2 : Suppose a sample of 595 people is drawn. Of these people, 315 passed out at G forces greater than 6. Using the data, estimate the proportion of people who pass out at more than 6 Gs. Enter your answer as a fraction or a decimal number rounded to three decimal places.
Suppose μ₁ and ₂ are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 8, x = 115.6, $₁=5.09, n = 8, y = 129.5, and s₂ = 5.33. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) USE SALT Does the interval suggest that precise information about the value of this difference is available? O Because the interval is so narrow, it appears that precise information is available. O Because the interval is so wide, it appears that precise information is available. O Because the interval is so narrow, it appears that precise information is not available. O Because the interval is so wide, it appears that precise information is not available.
NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. Step 1 of 2: Suppose a sample of 502 people is drawn. Of these people, 140 passed out at G forces greater than 6. Using the data, estimate the proportion of people who pass out at more than 6 Gs. Enter your answer as a fraction or a decimal number rounded to three decimal places.
Note: Use a computer application (SPSS) to solve for the following problems.
A number of studies have shown lichens (certain plants composed of an alga and a fungus) to be excellent bio-indicators of air pollution. An article gives the following data (n = 13) on x = NO3- wet deposition (g N/m²) and y = lichen (% dry weight): x 0.05 0.10 0.11 0.12 0.31 0.37 0.42 0.58 0.68 0.68 0.73 0.85 0.92 y 0.53 0.58 0.45 0.54 0.57 0.53 1.03 0.89 0.90 1.02 0.91 1.00 1.66 Predictor Constant no3 depo Estimate 0.39329 0.9286 0.1767 S = 0.1866 R-sq = 71.5% Standard Error 0.09566 t Stat 4.11 5.26 p-value 0.002 0.000 R-sq (adj) = 68.9% (a) What are the least square estimates of B and ẞ₁? (Round your answers to three decimal places.) bo = = (b) What is the margin of error for a 95% CI for ẞ₁? (Round your answer to four decimal places.) Margin of Error = (c) Predict lichen N for an NO3 - deposition value of 0.7. (Round your answer to three decimal places.) % dry weight (d) What is the estimate of σ? (Round your answer to four decimal places.) S = % dry weight
Your company manufactures plastic wrap for food storage. The tear resistance of the wrap, denoted by X, must be controlled so that the wrap can be torn off the roll without too much effort but it does not tear too easily when in use. In a series of tests (see data table below), 15 rolls of wrap are made under carefully controlled conditions and the tear resistance of each rool is measured. The results are used as the basis of a quality assurance specification. If X for a subsequently produced roll falls more than two standard deviations away from the test period average, the process is declared out of specification and production is suspended for routine maintenance. Roll 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 X 134 131 129 133 135 131 134 130 131 136 129 130 133 130 133 a)What is the mean tear resistance? Enter your answer to the correct number of significant figures. b)What is the…

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