late the test statistic and P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) 2-2.59 ✓ ✓ ue=0.0048 the conclusion in the problem context. ject Ho. The data suggests that the average heat output for sufferers is more than 1 cal/cm³/min below that of non-sufferers. all to reject Ho. The data suggests that the average heat output r sufferers is the same as that of non-sufferers. eject Ho. The data suggests that the average heat output for sufferers is the same as that of non-sufferers. all to reject H. The data suggests that the average heat output for sufferers is less than 1 cal/cm²/min below that of non-sufferers. that is the probability of a type II error when the actual difference between ₁ and ₂ is ₁-₂ -1.2? (Round your answer to four decimal places.) 10 x ssuming that m-n, what sample sizes are required to ensure that -0.1 when #₂ -₂ -1.2? (Round your answer up to the nearest whole number.) X subjects d to use the appropriate table in the Appendix of Tables to answer this question.

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Chapter1: Starting With Matlab
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I am unsure what I may be doing wrong for the bottom 2 question, (b) and (c) , that are giving me a hard time. 

Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experiment to study the extent of this impairment, each subject immersed a forefinger in water and the resulting heat output (cal/cm²/min) was measured. For m = 9 subjects with the syndrome, the
average heat output was x = 0.62, and for n = 9 nonsufferers, the average output was 2.06. Let μ₁ and μ₂ denote the true average heat outputs for the sufferers and nonsufferers, respectively. Assume that the two distributions of heat output are normal with ₁ = 0.1 and ₂ = 0.5.
(a) Consider testing Ho: M₁ M₂
= -1.0 versus H₂: M₁ M₂ < -1.0 at level 0.01. Describe in words what H₂ says, and then carry out the test.
O H₂ says that the average heat output for sufferers is less than 1 cal/cm²/min below that of non-sufferers.
ⒸH₂ says that the average heat output for sufferers is more than 1 cal/cm2/min below that of non-sufferers.
a
O H₂ says that the average heat output for sufferers is the same as that of non-sufferers.
Calculate the test statistic and P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.)
Z = -2.59
P-value = 0.0048
State the conclusion in the problem context.
Reject Ho. The data suggests that the average heat output for sufferers is more than 1 cal/cm²/min below that of non-sufferers.
O Fail to reject Ho. The data suggests that the average heat output for sufferers is the same as that of non-sufferers.
O Reject Ho. The data suggests that the average heat output for sufferers is the same as that of non-sufferers.
O Fail to reject Ho. The data suggests that the average heat output for sufferers is less than 1 cal/cm²/min below that of non-sufferers.
(b) What is the probability of a type II error when the actual difference between μ₁ and μ₂ is μ₁ −μ₂ = -1.2? (Round your answer to four decimal places.)
X
0.8300
(c) Assuming that m = n, what sample sizes are required to ensure that ß = 0.1 when M₁ M₂ = -1.2? (Round your answer up to the nearest whole number.)
X subjects
82
You may need to use the appropriate table in the Appendix of Tables to answer this question.
Transcribed Image Text:Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experiment to study the extent of this impairment, each subject immersed a forefinger in water and the resulting heat output (cal/cm²/min) was measured. For m = 9 subjects with the syndrome, the average heat output was x = 0.62, and for n = 9 nonsufferers, the average output was 2.06. Let μ₁ and μ₂ denote the true average heat outputs for the sufferers and nonsufferers, respectively. Assume that the two distributions of heat output are normal with ₁ = 0.1 and ₂ = 0.5. (a) Consider testing Ho: M₁ M₂ = -1.0 versus H₂: M₁ M₂ < -1.0 at level 0.01. Describe in words what H₂ says, and then carry out the test. O H₂ says that the average heat output for sufferers is less than 1 cal/cm²/min below that of non-sufferers. ⒸH₂ says that the average heat output for sufferers is more than 1 cal/cm2/min below that of non-sufferers. a O H₂ says that the average heat output for sufferers is the same as that of non-sufferers. Calculate the test statistic and P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) Z = -2.59 P-value = 0.0048 State the conclusion in the problem context. Reject Ho. The data suggests that the average heat output for sufferers is more than 1 cal/cm²/min below that of non-sufferers. O Fail to reject Ho. The data suggests that the average heat output for sufferers is the same as that of non-sufferers. O Reject Ho. The data suggests that the average heat output for sufferers is the same as that of non-sufferers. O Fail to reject Ho. The data suggests that the average heat output for sufferers is less than 1 cal/cm²/min below that of non-sufferers. (b) What is the probability of a type II error when the actual difference between μ₁ and μ₂ is μ₁ −μ₂ = -1.2? (Round your answer to four decimal places.) X 0.8300 (c) Assuming that m = n, what sample sizes are required to ensure that ß = 0.1 when M₁ M₂ = -1.2? (Round your answer up to the nearest whole number.) X subjects 82 You may need to use the appropriate table in the Appendix of Tables to answer this question.
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