You should use algebra in all parts of this question, showing your working clearly. (a) Solve the following equations, giving your answers as integers or as fractions in their simplest form. (i) 7a + 19 = 21 – 3x (ii) 14 – (9x – 2) = 7 + 3r 20 = 1 x + 2 x + 8 (b) Factorise the expression r? +13x – 68, and hence solve the equation x? + 13x – 68 = 0. (c) A student was asked to rearrange the formula d – 2c(6 – d) 10a 7 to make d the subject (assuming that 1+ 14c + 0). The student's incorrect attempt is shown below. 10 a =-206-d) Clear the fractions By multiplyinG By 7 10 a =d-20lb-d) Multiply out the Bracket 10 a = d-12c-2cd

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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You should use algebra in all parts of this question, showing your working
clearly.
(a) Solve the following equations, giving your answers as integers or as
fractions in their simplest form.
(i) 7a + 19 = 21 – 3x
(ii) 14 – (9x – 2) = 7 + 3r
20
= 1
x + 2
x + 8
(b) Factorise the expression r? +13x – 68, and hence solve the equation
x? + 13x – 68 = 0.
(c) A student was asked to rearrange the formula
d
– 2c(6 – d)
10a
7
to make d the subject (assuming that 1+ 14c + 0).
The student's incorrect attempt is shown below.
10a =-20b-d)
Clear the fractions By multiplyinG By 7
10 a =d-20lb-d)
Multiply out the Bracket
10 a = d-12c-2od
Collect the d terms
10 a+12c = d-2od
Factorise
10 a+12c = dl – 2c)
Divide By l-20 to Give
10 a +12c
d =
|-20
(i) Write out a correct rearrangement of the formula.
(ii) Identify and explain, as if directly to the student, two of the
mistakes they have made.
Transcribed Image Text:You should use algebra in all parts of this question, showing your working clearly. (a) Solve the following equations, giving your answers as integers or as fractions in their simplest form. (i) 7a + 19 = 21 – 3x (ii) 14 – (9x – 2) = 7 + 3r 20 = 1 x + 2 x + 8 (b) Factorise the expression r? +13x – 68, and hence solve the equation x? + 13x – 68 = 0. (c) A student was asked to rearrange the formula d – 2c(6 – d) 10a 7 to make d the subject (assuming that 1+ 14c + 0). The student's incorrect attempt is shown below. 10a =-20b-d) Clear the fractions By multiplyinG By 7 10 a =d-20lb-d) Multiply out the Bracket 10 a = d-12c-2od Collect the d terms 10 a+12c = d-2od Factorise 10 a+12c = dl – 2c) Divide By l-20 to Give 10 a +12c d = |-20 (i) Write out a correct rearrangement of the formula. (ii) Identify and explain, as if directly to the student, two of the mistakes they have made.
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