5(x+4)=9(x-3)-(2x+5)

Q: X^2+3x-18=(x-3)(x+a)

A: Given that x2 + 3x - 18 =( x - 3 ) ( x + a ) we have to find value of a.  For this let us first…

Q: 2(x -3) – (4x + 5)

A:

Q: how did you get the "x^2+x+1"?

A:

Q: 3(x+3)^2 and the answer is 3(x^2+6x+9) how do you get that answer.

A: Expanding (x+3)^2 :

Q: 4х + 6 1 25. (x² + 3x + 7)3 (x² + 3x + 7)3 (2x +3)

A:

Q: (c+d)^4 -1

A:

Q: (8y-20)^2=9

A: Given information:The given equation is

Q: (2x3-x-5) - (6x3+x-x+1)

A:

Q: 5(x + 3) = -5 - 5x

A:

Q: 2(3x - 1) = 2x + 4x - 2

A: NOTE: Refresh your page if you can't see any equations. .

Q: (7x2+4x-3)+(-9x3-x+5)-(x3-6x2+9) Simplify

A: (7x2+4x-3)+(-9x3-x+5)-(x3-6x2+9)

Q: (8x2 - 10) + (2x² - 3x - 4) 24x2 - 7x + 5) - (14x2 + 4x - 3) (x4)5

A:

Q: how did you get the (x^2+2x-3) twice? can you show that please?

A:

Q: 9(3x+2)-10x+12x-7

A: First we write the expression and distribute 9 over the terms in the parentheses of the expression

Q: 5x/ x2-x-12 - 2x-1 / x2-3x-4

A:

Q: 2(x+7)^2-2=6

A: Given expression is,

Q: X^2-4x-4=(x-2)^2

A: Given:     To determine: value of x

Q: 2(x+4)-7(8x-2)=16

A:

Q: 2y

A:

Q: 5(x−3)+11x=13(15x−3)

A: Given,           5x-3+11x=1315x-3

Q: 6x+3-(8x-5)

A: Given, 6x+3-(8x-5) we have to simplify it

Q: (4x²-3x+1)-(2x²-3x+4)

A:

Q: 7(3x+4)

A: Given expression is,

Q: 2 x² - 6x + 5 (-) 3x² - 2x - 2

A: x2-6x+5-3x2- 2x-2

Q: 4x^(2)+10x+4=(ax+1)(2x+d)

A: Given.

Q: (2k^{3}-3+7k^{2})+(8k^{3}+5k^{2}+6)

A:

Q: 5+ (6x (6x + 9) = -(x – 4) %3D

A: To solve 5+1/3(6x+9)=-(x-4)

Q: Divide (x4 + 7x3 - 5x2 + x - 11)/(x - 1)

A:

Q: x/x+9 + 2/x-4 = -2x+99/x2 +5x-36

A: The given equation is

Q: 5(8-x)=3x

A: First we open the bracket in the left hand side of the equation.

Q: 2(x + 3) - 7(2 - 3x)

A:

Q: (ax2+3ax)

A: Explanation and solutions is given below.....