5(x+4)=9(x-3)-(2x+5)

Q: (x² +5x-4) + (2x²+2x+3)

A: x2+5x-4+2x2+2x+3

Q: 46x^3+5)(3x+6)

A: (46x^3+5)(3x+6)

Q: X^2+3x-18=(x-3)(x+a)

A: Given that x2 + 3x - 18 =( x - 3 ) ( x + a ) we have to find value of a.  For this let us first…

Q: 2(x -3) – (4x + 5)

A:

Q: (3x+2) 20+30x b) = 4x²(3x+6) (x+2)

A: For any query with the solution, please ask in the comment box.

Q: 3(x+3)^2 and the answer is 3(x^2+6x+9) how do you get that answer.

A: Expanding (x+3)^2 :

Q: What 12x(14+5)-(7x6)

A: Consider

Q: (8y-20)^2=9

A: Given information:The given equation is

Q: (2x3-x-5) - (6x3+x-x+1)

A:

Q: 4x/(x2+9x+18) + 5/(x+6)

A: The given equation is; 4x/(x2+9x+18) + 5/(x+6)

Q: 5(x + 3) = -5 - 5x

A:

Q: X x² - 6x + 5 (-) 3x² - 2x - 2

A:

Q: (x*+ ラx*-x+3)=(*+ィス)

A:

Q: how did you get the (x^2+2x-3) twice? can you show that please?

A:

Q: 5x/ x2-x-12 - 2x-1 / x2-3x-4

A:

Q: 7(3x+6)=11-(x+2)

A: Given an algebraic equation. We shall solve the equation for x.

Q: 4(x + 8) = 2(4 + 2x)

A:

Q: x2+9x+20=(x+a)(x+b)

A:

Q: 5b2 (b2 - 4) = 112 - 39b2

A: The given equation to be solved is 5b2(b2–4) = 112–39b2.

Q: (4x²-3x+1)-(2x²-3x+4)

A:

Q: 2 x² - 6x + 5 (-) 3x² - 2x - 2

A: x2-6x+5-3x2- 2x-2

Q: 4x^(2)+10x+4=(ax+1)(2x+d)

A: Given.

Q: 8(x-4)=3x+29

A: We have to solve the given equation 8(x-4)=3x+29

Q: (2k^{3}-3+7k^{2})+(8k^{3}+5k^{2}+6)

A: