Problem 2: The Center for Disease Control (CDC) recommends in 2020 that children do not go "trick-or- treating" on Halloween due to the COVID-19 pandemic. However, many parents still plan on taking their kids out door-to-door for candy anyway. In order to find out more about the plans of parents in a small city, we would like to estimate the proportion of parents that plan on taking their children "trick-or- treating" on Halloween. We decide to take a randomly selected group of parents for a survey. If we estimate this proportion using a 90% confidence interval, approximately how many parents will we need to survey to be within a 5% margin of error?

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.3: Least Squares Approximation
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Problem 2: The Center for Disease Control (CDC) recommends in 2020 that children do not go "trick-or-
treating" on Halloween due to the COVID-19 pandemic. However, many parents still plan on taking their
kids out door-to-door for candy anyway. In order to find out more about the plans of parents in a small
city, we would like to estimate the proportion of parents that plan on taking their children "trick-or-
treating" on Halloween. We decide to take a randomly selected group of parents for a survey. If we
estimate this proportion using a 90% confidence interval, approximately how many parents will we need
to survey to be within a 5% margin of error?
Transcribed Image Text:Problem 2: The Center for Disease Control (CDC) recommends in 2020 that children do not go "trick-or- treating" on Halloween due to the COVID-19 pandemic. However, many parents still plan on taking their kids out door-to-door for candy anyway. In order to find out more about the plans of parents in a small city, we would like to estimate the proportion of parents that plan on taking their children "trick-or- treating" on Halloween. We decide to take a randomly selected group of parents for a survey. If we estimate this proportion using a 90% confidence interval, approximately how many parents will we need to survey to be within a 5% margin of error?
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