Problem 2: Please answer parts a, b, c, dAn observational study of Alzheimer's disease (AD) obtained data from 16 AD patients exhibiting moderate dementia and selected a group of 10 control individuals without AD. AD is a progressive neurodegenerative disease of the elderly and advancing age is known to be a primary risk factor in AD diagnosis. Therefore, it was crucial for the study's credibility to examine whether the ages in the AD group might be significantly different than in the control group. The ages of the subjects in years are summarized in the R Output below.-----------------------------------------------------------------------------------------------------------------------Descriptive Statistics: Alzheimers, ControlVariableNN*MeanSE MeanStDevMinimumQ1MedianQ3MaximumAlzheimers16079.761.676.6877.0079.2587.0092.2593.00Control10067.424.1012.9754.0056.0065.0082.0089.00-----------------------------------------------------------------------------------------------------------------------We want to test if the average age in the Alzheimer's group is significantly different than the control group. Assume that the population variances are not equal.(a)What is the null hypothesis?(A) H0 : μ1 = μ2 (B) H0 : μ1 ≠ μ2 (C) H0 : μ1 ≥ μ2 (D) H0 : μ1 < μ2 (E) H0 : μ1 > μ2 (F) H0 : μ1 ≤ μ2(b)Find the value of the test statistic.(c)Find the 5% critical value.(d)What is the conclusion of the hypothesis test? Problem #2: An observational study of Alzheimer's disease (AD) obtained data from 16 AD patients exhibiting moderatedementia and selected a group of 10 control individuals without AD. AD is a progressive neurodegenerativedisease of the elderly and advancing age is known to be a primary risk factor in AD diagnosis. Therefore, it wascrucial for the study's credibility to examine whether the ages in the AD group might be significantly differentthan in the control group. The ages of the subjects in years are summarized in the R Output below.Descriptive Statistics: Alzheimers, ControlVariableN N*Mean SE MeanStDev MinimumQ1 MedianQ3 Maximum79.7667.42Alzheimers161.676.6877.00 79.2587.00 92.2593.00Control104.10 12.9754.00 56.0065.00 82.0089.00We want to test if the average age in the Alzheimer's group is significantly different than the control group.Assume that the population variances are not equal.(a) What is the null hypothesis?(b) Find the value of the test statistic.(c) Find the 5% critical value.(d) What is the conclusion of the hypothesis test?(A) Ho : 41 = 42 (B) Ho : H1# !2 (C) Ho : H1ZH2 (D) Ho :H1 H2 (F) Ho:41<42

In order to determine whether the average age in the Alzheimer's group is significantly different…

Answered: Problem 2: Please answer parts a, b, c,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Problem 2: Please answer parts a, b, c, d

An observational study of Alzheimer's disease (AD) obtained data from 16 AD patients exhibiting moderate dementia and selected a group of 10 control individuals without AD. AD is a progressive neurodegenerative disease of the elderly and advancing age is known to be a primary risk factor in AD diagnosis. Therefore, it was crucial for the study's credibility to examine whether the ages in the AD group might be significantly different than in the control group. The ages of the subjects in years are summarized in the R Output below.

-----------------------------------------------------------------------------------------------------------------------
Descriptive Statistics: Alzheimers, Control

Variable	N	N*	Mean	SE Mean	StDev	Minimum	Q1	Median	Q3	Maximum
Alzheimers	16	0	79.76	1.67	6.68	77.00	79.25	87.00	92.25	93.00
Control	10	0	67.42	4.10	12.97	54.00	56.00	65.00	82.00	89.00

-----------------------------------------------------------------------------------------------------------------------

We want to test if the average age in the Alzheimer's group is significantly different than the control group. Assume that the population variances are not equal.

(a)	What is the null hypothesis?

(A) H₀ : μ₁ = μ₂ (B) H₀ : μ₁ ≠ μ₂ (C) H₀ : μ₁ ≥ μ₂ (D) H₀ : μ₁ < μ₂ (E) H₀ : μ₁ > μ₂ (F) H₀ : μ₁ ≤ μ₂

(b)	Find the value of the test statistic.

(c)	Find the 5% critical value.

(d)	What is the conclusion of the hypothesis test?

Problem #2: An observational study of Alzheimer's disease (AD) obtained data from 16 AD patients exhibiting moderate
dementia and selected a group of 10 control individuals without AD. AD is a progressive neurodegenerative
disease of the elderly and advancing age is known to be a primary risk factor in AD diagnosis. Therefore, it was
crucial for the study's credibility to examine whether the ages in the AD group might be significantly different
than in the control group. The ages of the subjects in years are summarized in the R Output below.
Descriptive Statistics: Alzheimers, Control
Variable
N N*
Mean SE Mean
StDev Minimum
Q1 Median
Q3 Maximum
79.76
67.42
Alzheimers
16
1.67
6.68
77.00 79.25
87.00 92.25
93.00
Control
10
4.10 12.97
54.00 56.00
65.00 82.00
89.00
We want to test if the average age in the Alzheimer's group is significantly different than the control group.
Assume that the population variances are not equal.
(a) What is the null hypothesis?
(b) Find the value of the test statistic.
(c) Find the 5% critical value.
(d) What is the conclusion of the hypothesis test?
(A) Ho : 41 = 42 (B) Ho : H1# !2 (C) Ho : H1ZH2 (D) Ho :H1<H2 (E) Ho:H1> H2 (F) Ho:41<42

Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

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