Problem #2) Given the following (steady-state) AC circuit: 카 100uF Is v(t) 100 m 50mH- VL v(t)=√√2.24.sin(@ot +30°) @=2π. f f = 60 Hz a) Express the source voltage in (RMS) phasor form and the R,L,C load values as impedances. b) Determine the source current and the inductor voltage V₁, both in phasor form. c) Express the source current is(t) and inductor voltage vi(t) as sinusoidal time functions.

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Problem #2) Given the following (steady-state) AC circuit:
카
Is 100uF
**--
v(t)
100 50mH
Problem #3) Given the following (steady-state) AC circuit:
카
Is
100uF
v(t)
100
Ohms
a) Express the source voltage in (RMS) phasor form and the R,L,C load values as impedances.
b) Determine the source current I, and the inductor voltage V₁, both in phasor form.
c) Express the source current is(t) and inductor voltage vi(t) as sinusoidal time functions.
M
50
Ohms
50mH
v(t)=√√2.24.sin(at +30°)
MacBook Pro
Q Search or enter website name
@=2π.f
f = 60 Hz
VL
a) Determine the source current I, and the inductor voltage V₁, both in phasor form.
b) Determine the total complex power, S, supplied by the source to the circuit.
v(t)=√√2-60-sin(@t-45°)
@= 2π f = 1000 rad/sec
Print
Transcribed Image Text:1 - + Automatic Zoom Problem #2) Given the following (steady-state) AC circuit: 카 Is 100uF **-- v(t) 100 50mH Problem #3) Given the following (steady-state) AC circuit: 카 Is 100uF v(t) 100 Ohms a) Express the source voltage in (RMS) phasor form and the R,L,C load values as impedances. b) Determine the source current I, and the inductor voltage V₁, both in phasor form. c) Express the source current is(t) and inductor voltage vi(t) as sinusoidal time functions. M 50 Ohms 50mH v(t)=√√2.24.sin(at +30°) MacBook Pro Q Search or enter website name @=2π.f f = 60 Hz VL a) Determine the source current I, and the inductor voltage V₁, both in phasor form. b) Determine the total complex power, S, supplied by the source to the circuit. v(t)=√√2-60-sin(@t-45°) @= 2π f = 1000 rad/sec Print
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