Parts B and C. Learning Goal:To use information about the power provided by a source or absorbed by a loadto calculate average power, reactive power, apparent power, and the powerfactor.Before completing this tutorial, make sure you are familiar with the relationshipsbetween average, reactive, and apparent power and the power factor.Part A - Calculating average power, reactive power, and the power factorA load absorbs S = 18 kVA at a leading power factor of pf = 0.90. Use this information to calculate the average (P) and reactive (Q) power for the load.Enter comma separated numerical answers with three significant figures.► View Available Hint(s)P, Q = 16.2,-7.85 kW, KVARSubmitCorrectTerm 2: Correct answer is shown. Your answer -7.846 kW, kVAR was either rounded differently or used a different number of significant figures than required for this part.Keep in mind that the power triangle requires that the average and reactive powers be numerically smaller in value than the apparent powerPart B - Calculating apparent power and power factorA load operates at a voltage of V₂ = 100 V-rms and absorbs P = 70 W and Q = 37 VAR of power. Use this information to calculate the apparent power (S) and the power factor (pf) for theload.Enter comma separated numerical answers with three significant figures.► View Available Hint(s)S, pf =Previous AnswersSubmitZ =VG | ΑΣΦPart C - Calculating load impedanceSubmit↓↑ vecA load absorbs 45403 W at a lagging power factor of pf = 0.57. If the current flowing through the load is i = 0.001 A-rms, determine the impedance of the load.Enter a complex number with three significant figures.► View Available Hint(s)ΞΑΣΦ↓↑ vec??VA, no unitΩ

Part ( B ) :Supply voltage Active power P = 70 W.Reactive power Q = 37 VAR.Apparant power is given by,Power factor is given by,Part (c) :Power absorbed by the load P = 45403 W.Lagging power factor Load current Power is given by,Impedance is given by,Part (B) :Apparant power S = 79.172 VA.Power factor = 0.884.Part (C) :Impedance