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Problem 2: A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the block. The bullet's mass is m = 0.0055 kg, while that of the block is M = 0.96 kg. After the collision the block/bullet system swings and reaches a maximum height of h = 11 m above its initial height. Neglect air resistance.

Problem 2: A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the block. The bullet's mass is m = 0.0055 kg, while that of the block is M = 0.96 kg. After the collision the block/bullet system swings and reaches a maximum height of h = 11 m above its initial height. Neglect air resistance.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please answer question 2 parts f and g, the parts before are answered. The question is not incomplete and everything is there to answer those parts

Problem 2: A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the block. The bullet's mass is m = 0.0055 kg, while that of the block is M = 0.96 kg. After the collision the block/bullet system swings and reaches a maximum height of h = 1.1 m above its initial height. Neglect air resistance. Part (a) Enter an expression for the speed of the block/bullet system immediately after the collision in terms of defined quantities and g. Expression_: Select from the variables below to write your expression. Note that all variables may not be required. B, Y, 0, b, c, d, g, h, j, k, m, M, n, P, S Part (b) Find the speed of the block/bullet system, in meters per second, immediately after the collision. Numeric : A numeric value is expected and not an expression. Vi = 4.643 Part (c) Enter an expression for the initial speed of the bullet in terms of defined quantities and g. Expression : v; = ((m+M) (V(zgn)) Im) Select from the variables below to write your expression. Note that all variables may not be required. В, у. Ө, b, с, d, g. h,j, k, m, M, п, Р, S Part (d) Find the initial speed of the bullet, in meters per second. Numeric : A numeric value is expected and not an expression. Vi =, 315.1 Part (e) Find the initial kinetic energy of the bullet, in joules. Numeric : A numeric value is expected and not an expression. KE; =. 1827 Part (f) Enter an expression for the kinetic energy of the block/bullet system immediately after the collision, in terms of defined quantities and g. Expression : KEf = Select from the variables below to write your expression. Note that all variables may not be required. B, Y, 0, b, c, d, g, h, j, k, m, M, n, P, S Part (g) Calculate the ratio, expressed as a percent, of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet. Numeric : A numeric value is expected and not an expression. KEAKE;(%) =
Transcribed Image Text:Problem 2: A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the block. The bullet's mass is m = 0.0055 kg, while that of the block is M = 0.96 kg. After the collision the block/bullet system swings and reaches a maximum height of h = 1.1 m above its initial height. Neglect air resistance. Part (a) Enter an expression for the speed of the block/bullet system immediately after the collision in terms of defined quantities and g. Expression_: Select from the variables below to write your expression. Note that all variables may not be required. B, Y, 0, b, c, d, g, h, j, k, m, M, n, P, S Part (b) Find the speed of the block/bullet system, in meters per second, immediately after the collision. Numeric : A numeric value is expected and not an expression. Vi = 4.643 Part (c) Enter an expression for the initial speed of the bullet in terms of defined quantities and g. Expression : v; = ((m+M) (V(zgn)) Im) Select from the variables below to write your expression. Note that all variables may not be required. В, у. Ө, b, с, d, g. h,j, k, m, M, п, Р, S Part (d) Find the initial speed of the bullet, in meters per second. Numeric : A numeric value is expected and not an expression. Vi =, 315.1 Part (e) Find the initial kinetic energy of the bullet, in joules. Numeric : A numeric value is expected and not an expression. KE; =. 1827 Part (f) Enter an expression for the kinetic energy of the block/bullet system immediately after the collision, in terms of defined quantities and g. Expression : KEf = Select from the variables below to write your expression. Note that all variables may not be required. B, Y, 0, b, c, d, g, h, j, k, m, M, n, P, S Part (g) Calculate the ratio, expressed as a percent, of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet. Numeric : A numeric value is expected and not an expression. KEAKE;(%) =
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