Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
Make a ray diagram for an object between the focal length and the center of curvature a thin concave-concave lens. Also include a calculation of the focal length should be, using an equation.  If your image is virtual, you should plug a negative number in for the corresponding variable of the lens equation. Measure the focal length, and see whether they are similar, provide explanation

Make a ray diagram for an object between the focal length and the center of curvature a thin concave-concave lens. Also include a calculation of the focal length should be, using an equation.  If your image is virtual, you should plug a negative number in for the corresponding variable of the lens equation. Measure the focal length, and see whether they are similar, provide explanation

icon
Related questions
Question

Make a ray diagram for an object between the focal length and the center of curvature a thin concave-concave lens.

Also include a calculation of the focal length should be, using an equation.  If your image is virtual, you should plug a negative number in for the corresponding variable of the lens equation.

Measure the focal length, and see whether they are similar, provide explanation

Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

Can you verify the equation because in the image it provides that the thin lens equation is 1/s+1/s'=1/f

The height ratio is h'/h = |m|. m is + for an upright image, - for inverted. Chapter 34: Ray Optics Thin lenses The image and object distances are related by R -14 1 S where the focal length is given by the lens maker's equation: 1 +--- S 1 f - = (n − 1) (₁ - 1₂) + for surface convex toward object + for a converging lens + for a real image Focal length f S D - for concave - for diverging - for virtual FI
Transcribed Image Text:The height ratio is h'/h = |m|. m is + for an upright image, - for inverted. Chapter 34: Ray Optics Thin lenses The image and object distances are related by R -14 1 S where the focal length is given by the lens maker's equation: 1 +--- S 1 f - = (n − 1) (₁ - 1₂) + for surface convex toward object + for a converging lens + for a real image Focal length f S D - for concave - for diverging - for virtual FI
Solution
Bartleby Expert
SEE SOLUTION
Follow-up Question

so your original focal length is 2cm but when you used the formula to verify this answer your answer comes out to be -2cm so is the original focal length supposed to be negative because how does 2cm=-2cm 

Solution
Bartleby Expert
SEE SOLUTION
Follow-up Question

which value did you compare it with to say that they both agree without any deviation also what does U and V mean on the diagram that you drew because you did not label U and V as well as which parts you measured. 

Solution
Bartleby Expert
SEE SOLUTION
Follow-up Question

why are you using that formula and not this one 

1/F=1/O+1/I

F= 1/(1/O+1/I) 

 

Solution
Bartleby Expert
SEE SOLUTION
Similar questions