Problem 15. In the case of a particle tunneling through the barrier, we made equal both functions and derivatives at the boundary between region I and II, and between II and III, see eq. (9a – 9d). But in the case of the particle in the box, we made both functions equal at x = 0 and at x = L. Explain why we did not consider derivatives in this case.
Problem 15. In the case of a particle tunneling through the barrier, we made equal both functions and derivatives at the boundary between region I and II, and between II and III, see eq. (9a – 9d). But in the case of the particle in the box, we made both functions equal at x = 0 and at x = L. Explain why we did not consider derivatives in this case.
Related questions
Question
![Problem 15. In the case of a particle tunneling through the barrier, we made equal both functions
and derivatives at the boundary between region I and II, and between II and III, see eq. (9a – 9d).
But in the case of the particle in the box, we made both functions equal at x = 0 and at x = L.
Explain why we did not consider derivatives in this case.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1715d4a8-c6c1-4a7c-b9e4-652acc572a9b%2Ffacbb866-4240-4d8c-9a74-09889d198676%2Fxku04o_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 15. In the case of a particle tunneling through the barrier, we made equal both functions
and derivatives at the boundary between region I and II, and between II and III, see eq. (9a – 9d).
But in the case of the particle in the box, we made both functions equal at x = 0 and at x = L.
Explain why we did not consider derivatives in this case.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)