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Problem 13. A particle is projected with speed v at an angle 0 to the horizontal from the point æ = 0, y = 0. If x and y- axes are horizontal and vertically upwards respectively and point of projection is the lowest point on the inner surface of a bowl formed by rotating the curve æ? = 4ay, where a is a positive constant. Show that the particle strikes the bowl at a horizontal distance 4av? tan 0 v2 + 2ag + 2ag tan? 0

Problem 13. A particle is projected with speed v at an angle 0 to the horizontal from the point æ = 0, y = 0. If x and y- axes are horizontal and vertically upwards respectively and point of projection is the lowest point on the inner surface of a bowl formed by rotating the curve æ? = 4ay, where a is a positive constant. Show that the particle strikes the bowl at a horizontal distance 4av? tan 0 v2 + 2ag + 2ag tan? 0

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Problem 13. A particle is projected with speed v at an angle 0 to the horizontal from the point æ = 0, y = 0. If x and y - axes are horizontal and vertically upwards respectively and point of projection is the lowest point on the inner surface of a bowl formed by rotating the curve 2? = 4ay, where a is a positive constant. Show that the particle strikes the bowl at a horizontal distance 4av? tan 0 x = v2 + 2ag + 2ag tan? 0
Transcribed Image Text:Problem 13. A particle is projected with speed v at an angle 0 to the horizontal from the point æ = 0, y = 0. If x and y - axes are horizontal and vertically upwards respectively and point of projection is the lowest point on the inner surface of a bowl formed by rotating the curve 2? = 4ay, where a is a positive constant. Show that the particle strikes the bowl at a horizontal distance 4av? tan 0 x = v2 + 2ag + 2ag tan? 0
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