A golf ball is hit from the edge of a small cliff in such a way that it goes through a basketball hoop as shown in the figure below. The golf ball is launched with an initial speed v, = 10 m/s at an angle 0 such that cos(8) = 3/5 and sin(8) = 4/5. The basketball hoop is at the same height as the small cliff, which is equal to H = 12 m, and you may approximate the acceleration due to gravity as g = 10 m/s². H

A golf ball is hit from the edge of a small cliff in such a way that it goes through a basketball hoop as shown in the figure below. The golf ball is launched with an initial speed v, = 10 m/s at an angle 0 such that cos(8) = 3/5 and sin(8) = 4/5. The basketball hoop is at the same height as the small cliff, which is equal to H = 12 m, and you may approximate the acceleration due to gravity as g = 10 m/s². H

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Description: A golf ball is hit from the edge of a small cliff in such a way that it goes through a basketball hoop as shown in thefigure below. The golf ball is launched with an initial speed v, = 10 m/s at an angle 0 such that cos(8) = 3/5 andsin(8) = 4/5. The

College Physics

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Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A golf ball is hit from the edge of a small cliff in such a way that it goes through a basketball hoop as shown in the
figure below. The golf ball is launched with an initial speed v, = 10 m/s at an angle 0 such that cos(8) = 3/5 and
sin(8) = 4/5. The basketball hoop is at the same height as the small cliff, which is equal to H = 12 m, and you may
approximate the acceleration due to gravity as g = 10 m/s².
H

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