Danielle launches a ball off of a platform of height h with velocity vo at an angle 0 above the horizontal. A wall with a ball-sized hole a height H above the floor, with H > h, is a horizontal distance L = 24.0 m away from Danielle. The difference in height between H and h is one-twelfth of L, and the square of the magnitude of the velocity, v, is three-halves of the product gL. H 1 H – h = h 3 L Determine the two values of 0 that ensure the ball passes through the hole. Submit the larger angle as 0, and the smaller angle as 02.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Danielle launches a ball off of a platform of height h with
velocity vo at an angle 0 above the horizontal. A wall with a
ball-sized hole a height H above the floor, with H > h, is a
horizontal distance L = 24.0 m away from Danielle. The
difference in height between H and h is one-twelfth of L,
and the square of the magnitude of the velocity, v, is
three-halves of the product gL.
H
1
H – h =
h
3
L
Determine the two values of 0 that ensure the ball
passes
through the hole. Submit the larger angle as 0, and the
smaller angle as 02.
Transcribed Image Text:Danielle launches a ball off of a platform of height h with velocity vo at an angle 0 above the horizontal. A wall with a ball-sized hole a height H above the floor, with H > h, is a horizontal distance L = 24.0 m away from Danielle. The difference in height between H and h is one-twelfth of L, and the square of the magnitude of the velocity, v, is three-halves of the product gL. H 1 H – h = h 3 L Determine the two values of 0 that ensure the ball passes through the hole. Submit the larger angle as 0, and the smaller angle as 02.
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