Problem 13: A long, straight pipe made of non-conducting material has an inner radius of 15.0 cm and an outer radius of 25.0 cm. The pipe has a uniform charge density of 28 C/m³. Part (a) Calculate the Electric field (in N/C) a distance of r = 1.59 cm from the center of the pipe. E = Part (b) Calculate the Electric field (in N/C) a distance of ry = 16.69 cm from the center of the pipe. E = Part (c) Calculate the Electric field (in N/C) a distance of rz = 30.27 cm from the center of the pipe. E =
Problem 13: A long, straight pipe made of non-conducting material has an inner radius of 15.0 cm and an outer radius of 25.0 cm. The pipe has a uniform charge density of 28 C/m³. Part (a) Calculate the Electric field (in N/C) a distance of r = 1.59 cm from the center of the pipe. E = Part (b) Calculate the Electric field (in N/C) a distance of ry = 16.69 cm from the center of the pipe. E = Part (c) Calculate the Electric field (in N/C) a distance of rz = 30.27 cm from the center of the pipe. E =
Related questions
Question
100%
E6P13
Transcribed Image Text:Problem 13: A long, straight pipe made of non-conducting material has an inner radius of 15.0 cm and an outer radius of 25.0 cm. The
pipe has a uniform charge density of 28 C/m³.
Part (a) Calculate the Electric field (in N/C) a distance of r = 1.59 cm from the center of the pipe.
E =
Part (b) Calculate the Electric field (in N/C) a distance of r2 = 16.69 cm from the center of the pipe.
E =
Part (c) Calculate the Electric field (in N/C) a distance of r3 = 30.27 cm from the center of the pipe.
E =
Expert Solution
Step 1
Given information:
the inner radius of the pipe (ri) = 15.0 cm = 0.15 m
The outer radius of the pipe (ro) = 25 cm = 0.25 m
The charge density of the pipe (λ) = 28 C/m3
Let us draw the given scenario:
Step by step
Solved in 4 steps with 2 images
