Problem 6: In the figure below a 0.001 kg bullet with initial speed v₁ = 1800 m/sec is fired into a 0.5 kg block attached to the end of a 0.60 m rod of mass 0.50 kg. Point A is the pivot point for the rod and the bullet stays inside the block after the collision. What is the angular speed w of the system after the collision? The moment of inertia of the rod about point A is I = 1/3 M ² and the moment of a particle is I = mr². Treat the block as a particle and also treat the bullet as a particle. Answer: w = 4.5 rad/sec Bullet A Rod Block

Problem 6: In the figure below a 0.001 kg bullet with initial speed v₁ = 1800 m/sec is fired into a 0.5 kg block attached to the end of a 0.60 m rod of mass 0.50 kg. Point A is the pivot point for the rod and the bullet stays inside the block after the collision. What is the angular speed w of the system after the collision? The moment of inertia of the rod about point A is I = 1/3 M ² and the moment of a particle is I = mr². Treat the block as a particle and also treat the bullet as a particle. Answer: w = 4.5 rad/sec Bullet A Rod Block

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Torque

Torque is the rotational equivalent of linear force in physics and mechanics. Based on the course of study, it is also known as the moment of force, rotational force, or turning effect.

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Problem 6:
In the figure below a 0.001 kg bullet with initial speed v₁ = 1800 m/sec is fired into a 0.5 kg
block attached to the end of a 0.60 m rod of mass 0.50 kg. Point A is the pivot point for the rod
and the bullet stays inside the block after the collision. What is the angular speed w of the
system after the collision? The moment of inertia of the rod about point A is I = 1/3 M 1² and
the moment of a particle is I = mr². Treat the block as a particle and also treat the bullet as a
particle. Answer: w = 4.5 rad/sec
Bullet
A
Rod
Block

KE = mv², KE = 1w², Ug = mgh, U₁ = ¹kx², E = KE + Ug + Us, E₁ = Ef
L = mrv, 1 =1w

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