A solid sphere of mass m and radius r rolls without slipping (v=rw) along the track shown in the figure below. It starts from rest with the lowest point of the sphere at height h above the bottom of the loop of radius R, much larger than r. What is the minimum value of h (in terms of R) such that the sphere completes the loop? The moment of inertia of a sphere is I = mr².

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Chapter1: Units, Trigonometry. And Vectors
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Problem 3:
A solid sphere of mass m and radius r rolls without slipping (v=rw) along the track shown in
the figure below. It starts from rest with the lowest point of the sphere at height h above the
bottom of the loop of radius R, much larger than r. What is the minimum value of h (in terms
of R) such that the sphere completes the loop? The moment of inertia of a sphere is I = mr².
Hint: You will need to draw a free-body diagram of the ball at the top of the loop and you will
need to find the minimum speed the ball needs to complete the loop. Recall that the
centripetal acceleration is a =v²/R. Answer: h= (27/10) R = 2.7 R.
Solid sphere of mass m
and radius r << R.
R
Transcribed Image Text:Problem 3: A solid sphere of mass m and radius r rolls without slipping (v=rw) along the track shown in the figure below. It starts from rest with the lowest point of the sphere at height h above the bottom of the loop of radius R, much larger than r. What is the minimum value of h (in terms of R) such that the sphere completes the loop? The moment of inertia of a sphere is I = mr². Hint: You will need to draw a free-body diagram of the ball at the top of the loop and you will need to find the minimum speed the ball needs to complete the loop. Recall that the centripetal acceleration is a =v²/R. Answer: h= (27/10) R = 2.7 R. Solid sphere of mass m and radius r << R. R
KE = mv², KE = 1w², Ug = mgh, U₁ = ¹kx², E = KE + Ug + Us, E₁ = Ef
L = mrv, 1 =1w
Transcribed Image Text:KE = mv², KE = 1w², Ug = mgh, U₁ = ¹kx², E = KE + Ug + Us, E₁ = Ef L = mrv, 1 =1w
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