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Problem 12: A positively charged particle Q1 = +5 nC is held fixed at the origin. A second charge 22 of mass m = 3.5 µg is floating a distance d = 25 cm above charge Q₁. The net force on Q₂ is equal to ero. You may assume this system is close to the surface of the Earth. Q₂ d

Problem 12: A positively charged particle Q1 = +5 nC is held fixed at the origin. A second charge 22 of mass m = 3.5 µg is floating a distance d = 25 cm above charge Q₁. The net force on Q₂ is equal to ero. You may assume this system is close to the surface of the Earth. Q₂ d

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Part (a)  Calculate the magnitude of Q2 in units of nano coulombs. 

|Q2| = ______

### Problem 12: A positively charged particle \( Q_1 = +5 \, \text{nC} \) is held fixed at the origin. A second charge \( Q_2 \) of mass \( m = 3.5 \, \mu\text{g} \) is floating a distance \( d = 25 \, \text{cm} \) above charge \( Q_1 \). The net force on \( Q_2 \) is equal to zero. You may assume this system is close to the surface of the Earth. #### Explanation of the Diagram: The diagram provided shows two charges, \( Q_1 \) and \( Q_2 \). - \( Q_1 \) is positioned at the origin (bottom of the diagram) and is labeled with its charge. - \( Q_2 \) is positioned directly above \( Q_1 \) at a distance \( d \) and is labeled with its charge. - The distance \( d \) between \( Q_1 \) and \( Q_2 \) is denoted in the diagram as a vertical line separating the two charges. For the net force on \( Q_2 \) to be zero, the upward electric force due to \( Q_1 \) must balance the downward gravitational force acting on \( Q_2 \). This balance of forces ensures that \( Q_2 \) remains stationary at a distance \( d \) above \( Q_1 \).
Transcribed Image Text:### Problem 12: A positively charged particle \( Q_1 = +5 \, \text{nC} \) is held fixed at the origin. A second charge \( Q_2 \) of mass \( m = 3.5 \, \mu\text{g} \) is floating a distance \( d = 25 \, \text{cm} \) above charge \( Q_1 \). The net force on \( Q_2 \) is equal to zero. You may assume this system is close to the surface of the Earth. #### Explanation of the Diagram: The diagram provided shows two charges, \( Q_1 \) and \( Q_2 \). - \( Q_1 \) is positioned at the origin (bottom of the diagram) and is labeled with its charge. - \( Q_2 \) is positioned directly above \( Q_1 \) at a distance \( d \) and is labeled with its charge. - The distance \( d \) between \( Q_1 \) and \( Q_2 \) is denoted in the diagram as a vertical line separating the two charges. For the net force on \( Q_2 \) to be zero, the upward electric force due to \( Q_1 \) must balance the downward gravitational force acting on \( Q_2 \). This balance of forces ensures that \( Q_2 \) remains stationary at a distance \( d \) above \( Q_1 \).
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