What is the potential difference across a 17.0 m long, 2.00 mm diameter copper wire carrying an 7.30 A current?
What is the potential difference across a 17.0 m long, 2.00 mm diameter copper wire carrying an 7.30 A current?
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![**Part A**
**Problem Statement:**
What is the potential difference across a 17.0 m long, 2.00 mm diameter copper wire carrying a 7.30 A current?
**Input Box:**
An interactive field is provided for students to input their answer. The area allows the insertion of mathematical symbols and expressions using the toolbar at the top of the input box. Symbols include:
- \( x^a \): For exponents.
- \( x_b \): Subscripts.
- \( \frac{a}{b} \): Fractions.
- \( \sqrt{x} \): Square roots.
- \( \sqrt[3]{x} \): Cube roots and other radicals.
- \( \hat{x} \): Unit vectors.
- \( |x| \): Absolute value.
- \( x \cdot 10^n \): Scientific notation.
**Solution Box:**
Students are expected to enter their calculated potential difference (\(\Delta V\)) in volts (V) in the designated box below the interactive toolbar.
**Guide for Students:**
To solve this problem, use the formula for potential difference (\(\Delta V\)) in a resistive conductor: \( \Delta V = I \cdot R \), where:
- \( I \) is the current (7.30 A),
- \( R \) is the resistance of the wire.
The resistance \( R \) can be calculated using \( R = \rho \cdot \frac{L}{A} \), where:
- \( \rho \) is the resistivity of copper,
- \( L \) is the length of the wire (17.0 m),
- \( A \) is the cross-sectional area of the wire (\( \pi \cdot (d/2)^2 \) with \( d = 2.00 \) mm).
By calculating \( R \) and substituting back into the formula for \(\Delta V\), students can find the potential difference.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F74be4292-7d75-4748-a8da-51953667dfbc%2F57bd7fcd-429d-4327-a83a-bc055cdb0265%2Fauqwrm_processed.png&w=3840&q=75)
Transcribed Image Text:**Part A**
**Problem Statement:**
What is the potential difference across a 17.0 m long, 2.00 mm diameter copper wire carrying a 7.30 A current?
**Input Box:**
An interactive field is provided for students to input their answer. The area allows the insertion of mathematical symbols and expressions using the toolbar at the top of the input box. Symbols include:
- \( x^a \): For exponents.
- \( x_b \): Subscripts.
- \( \frac{a}{b} \): Fractions.
- \( \sqrt{x} \): Square roots.
- \( \sqrt[3]{x} \): Cube roots and other radicals.
- \( \hat{x} \): Unit vectors.
- \( |x| \): Absolute value.
- \( x \cdot 10^n \): Scientific notation.
**Solution Box:**
Students are expected to enter their calculated potential difference (\(\Delta V\)) in volts (V) in the designated box below the interactive toolbar.
**Guide for Students:**
To solve this problem, use the formula for potential difference (\(\Delta V\)) in a resistive conductor: \( \Delta V = I \cdot R \), where:
- \( I \) is the current (7.30 A),
- \( R \) is the resistance of the wire.
The resistance \( R \) can be calculated using \( R = \rho \cdot \frac{L}{A} \), where:
- \( \rho \) is the resistivity of copper,
- \( L \) is the length of the wire (17.0 m),
- \( A \) is the cross-sectional area of the wire (\( \pi \cdot (d/2)^2 \) with \( d = 2.00 \) mm).
By calculating \( R \) and substituting back into the formula for \(\Delta V\), students can find the potential difference.
Transcribed Image Text:Household wiring often uses 2.00 mm diameter copper wires. The wires can get rather long as they snake through the walls from the fuse box to the farthest corners of your house.
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