Problem 1. Each of the following assembly code snippets corresponds to the body of a C function consisting of a single control structure: a loop, if statement, or case switch. (Compiler directives, like cfi_startproc, and instructions that do not affect the semantics, like endbr64, have been removed for readability. And yes, of course the functions are all named foo.) For each one, write C code that would compile to similar assembly for the body. In other words, figure out what the code is doing and write C code to do that. You will have to figure out how many variables are being computed with, and make up names for them. (The code was compiled with -Og.)

Problem 1. Each of the following assembly code snippets corresponds to the body of a C function consisting of a single control structure: a loop, if statement, or case switch. (Compiler directives, like cfi_startproc, and instructions that do not affect the semantics, like endbr64, have been removed for readability. And yes, of course the functions are all named foo.) For each one, write C code that would compile to similar assembly for the body. In other words, figure out what the code is doing and write C code to do that. You will have to figure out how many variables are being computed with, and make up names for them. (The code was compiled with -Og.)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Class

Object Oriented Programming System (OOPs) is a programming model built on the perception of “objects” that contains data and methods. The major purpose of Object Oriented Programming is to increase the maintainability and flexibility of programs. Object Oriented Programming gets together data and its behavior (methods) in a single location (object) which makes it easier to understand.

Question

Problem 1. Each of the following assembly code snippets corresponds to the body of a C function
consisting of a single control structure: a loop, if statement, or case switch. (Compiler directives,
like cfi_startproc, and instructions that do not affect the semantics, like endbr64, have been
removed for readability. And yes, of course the functions are all named foo.) For each one, write
C code that would compile to similar assembly for the body. In other words, figure out what the
code is doing and write C code to do that. You will have to figure out how many variables are being
computed with, and make up names for them. (The code was compiled with -0g.)
foo:
a.
b.
C.
.L3:
.L2:
foo:
.L2:
foo:
.L3:
.L2:
movl $0, %edx
movl $0, %eax
jmp .L2
addl
(%rdi), %edx
addl
$1, %eax
leaq 4(%rdi), %rdi
cmp1 %esi, %eax
jl
.L3
movl
%edx, %eax
ret
movl (%rdi), %eax
cmpl $10, %eax
jle .L2
subl $10, %eax
movl %eax, (%rdi)
ret
leal 1(%rax,%rax, 2), %eax
movl %eax, (%rdi)
ret
movl $0, %eax
jmp .L2
addl $1, %eax
cmpb $0, (%rdi)
jne .L3
ret

d. (Note: this one has nested control structures. Hint: one is a conditional.)
foo:
.L3:
.L2:
.L5:
movl $0, %ecx
movl $0, %eax
jmp .L2
sarl %edi
sarl %esi
addl $1, %eax
cmp1 $31, %eax
jg .L5
movl %edi, %edx
xorl %esi, %edx
testb $1, %d1
jne
.L3
addl $1, %ecx
jmp
.L3
movl %ecx, %eax
ret
3

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