Problem 1. A balanced delta connected load of 15 +j18 2 per phase is connected at the end of a three- phase line as shown in the below figure. The line impedance is 1 + j2 2 per phase. The line is supplied from a three-phase source with a line-to-line voltage of 207.85 V (rms). 1+ j2 N |VL] = 207.85V bo 15 + j18 N www www Taking Vm as reference, determine the following: a) Current in phase a; b) Total complex power supplied from the source; c) Magnitude of the line-to-line voltage at the load terminal; d) The actual load current. Hint: Convert equivalently delta to wye connection.

Introductory Circuit Analysis (13th Edition)
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Problem 1. A balanced delta connected load of 15 + j18 Q per phase is connected at the end of a three-
phase line as shown in the below figure. The line impedance is 1+ j2 N per phase. The line is supplied
from a three-phase source with a line-to-line voltage of 207.85 V (rms).
1+ j2 N
wwm
a
|VL|
= 207.85 V
bo
15+ j18 N
Taking Vm as reference, determine the following:
a) Current in phase a;
b) Total complex power supplied from the source;
c) Magnitude of the line-to-line voltage at the load terminal;
d) The actual load current.
Hint: Convert equivalently delta to wye connection.
Transcribed Image Text:Problem 1. A balanced delta connected load of 15 + j18 Q per phase is connected at the end of a three- phase line as shown in the below figure. The line impedance is 1+ j2 N per phase. The line is supplied from a three-phase source with a line-to-line voltage of 207.85 V (rms). 1+ j2 N wwm a |VL| = 207.85 V bo 15+ j18 N Taking Vm as reference, determine the following: a) Current in phase a; b) Total complex power supplied from the source; c) Magnitude of the line-to-line voltage at the load terminal; d) The actual load current. Hint: Convert equivalently delta to wye connection.
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