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Problem 1 Sensor A reads 1.5 kPa (gauge). All fluids are at 20°C. Determine the elevation Z in meters of the liquid levels in the open piezometer tube C. Yair = 12 N/m³, v. Vglycerin = 12360 N/m³, Ygasoline = 6670 N/m³ 2 m 1.5 m 1m Air Gasoline Glycerin A B с Z=0

Problem 1 Sensor A reads 1.5 kPa (gauge). All fluids are at 20°C. Determine the elevation Z in meters of the liquid levels in the open piezometer tube C. Yair = 12 N/m³, v. Vglycerin = 12360 N/m³, Ygasoline = 6670 N/m³ 2 m 1.5 m 1m Air Gasoline Glycerin A B с Z=0

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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can someone please explain how did they get (6670*(1.5-H)-6670(=Zb-H-1) to calculate Zb

and how did they get 12360*(1-y)-12360*(Zc-y) to calculate Zc..i don't understand. Thanks

Problem 1 2 m Sensor A reads 1.5 kPa (gauge). All fluids are at 20°C. Determine the elevation Z in meters of the liquid levels in the open piezometer tube C. 1.5 m Yair = 12 N/m³. Yglycerin = 12360 N/m³, Ygasoline = 6670 N/m³ 1m 1500 N/m² + (12.0 N/m³)(2.0 m) +6670(1.5-H)-6670(ZB -H-1.0)=PB = 0 (gage) Solve for ZB=2.73 m (23 cm above the gasoline-air interface) Ans. (b) Solution (C): Let piezometer tube C be an arbitrary distance Y above the bottom. Then 1500+ 12.0(2.0) + 6670(1.5) + 12360(1.0-Y)-12360(ZC - Y) = pc = 0 (gage) Solve for ZC = 1.93 m (93 cm above the gasoline-glycerin interface) Ans. (c) Air Gasoline Glycerin A B C Z=0
Transcribed Image Text:Problem 1 2 m Sensor A reads 1.5 kPa (gauge). All fluids are at 20°C. Determine the elevation Z in meters of the liquid levels in the open piezometer tube C. 1.5 m Yair = 12 N/m³. Yglycerin = 12360 N/m³, Ygasoline = 6670 N/m³ 1m 1500 N/m² + (12.0 N/m³)(2.0 m) +6670(1.5-H)-6670(ZB -H-1.0)=PB = 0 (gage) Solve for ZB=2.73 m (23 cm above the gasoline-air interface) Ans. (b) Solution (C): Let piezometer tube C be an arbitrary distance Y above the bottom. Then 1500+ 12.0(2.0) + 6670(1.5) + 12360(1.0-Y)-12360(ZC - Y) = pc = 0 (gage) Solve for ZC = 1.93 m (93 cm above the gasoline-glycerin interface) Ans. (c) Air Gasoline Glycerin A B C Z=0
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