Problem 1 ( m/sis sliding on a horizontal floor, where the coefficient of kinetic friction is equal to 0. 5. At the end, the block comes to a stop. (Take g=9.8 m/s?). ) A block of mass m=15 Kg with initial velocity <13, 0,0 > a) ( ) Calculate the initial momentum of the block? b) Calculate the final momentum of the block? c)/* ) What is the change in the momentum of the block?

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Chapter1: Units, Trigonometry. And Vectors
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) A block of mass m=15 Kg with initial velocity <13, 0,0 >
m/s is sliding on a horizontal floor, where the coefficient of kinetic friction is
equal to 0. 5. At the end, the block comes to a stop. (Take g=9.8 m/s2).
Problem 1 ('
a) (
:) Calculate the initial momentum of the block?
=<
b)
Calculate the final momentum of the block?
c)
) What is the change in the momentum of the block?
Ap=<
d) (-) Find the magnitude of the normal force exerted by the floor on the
block.
|FN\=
e)
Find the magnitude of the friction force.
f) (!
) What is the direction of the friction force?
The friction force is directed along:
g)
) Find FNet·
FNet
h) (
How long will it takes to the block to come to a stop?
At =
Transcribed Image Text:) A block of mass m=15 Kg with initial velocity <13, 0,0 > m/s is sliding on a horizontal floor, where the coefficient of kinetic friction is equal to 0. 5. At the end, the block comes to a stop. (Take g=9.8 m/s2). Problem 1 (' a) ( :) Calculate the initial momentum of the block? =< b) Calculate the final momentum of the block? c) ) What is the change in the momentum of the block? Ap=< d) (-) Find the magnitude of the normal force exerted by the floor on the block. |FN\= e) Find the magnitude of the friction force. f) (! ) What is the direction of the friction force? The friction force is directed along: g) ) Find FNet· FNet h) ( How long will it takes to the block to come to a stop? At =
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