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Problem 1: Critical radius and supersaturation for Kohler curves Derive Eqs. (6.7) and (6.8) of Rogers and Yau (1989). That is, show that if we assume the equilibrium saturation ratio for a solution droplet is S = 1 + a r b 7-3¹ then the critical radius is r* = (3b/a)1/2 and the critical saturation ratio is S* = 1 + [4a³/(276)]¹/2.

Problem 1: Critical radius and supersaturation for Kohler curves Derive Eqs. (6.7) and (6.8) of Rogers and Yau (1989). That is, show that if we assume the equilibrium saturation ratio for a solution droplet is S = 1 + a r b 7-3¹ then the critical radius is r* = (3b/a)1/2 and the critical saturation ratio is S* = 1 + [4a³/(276)]¹/2.

Applications and Investigations in Earth Science (9th Edition)
Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
Section: Chapter Questions
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Reading: Rogers and Yau, Chpt. 6. Problem 1: Critical radius and supersaturation for Kohler curves Derive Eqs. (6.7) and (6.8) of Rogers and Yau (1989). That is, show that if we assume the equilibrium saturation ratio for a solution droplet is a S = 1+- r b p3' then the critical radius is r* = (3b/a)¹/2 and the critical saturation ratio is S* = 1 + [4a³/(276)]¹/2. voming sino
Transcribed Image Text:Reading: Rogers and Yau, Chpt. 6. Problem 1: Critical radius and supersaturation for Kohler curves Derive Eqs. (6.7) and (6.8) of Rogers and Yau (1989). That is, show that if we assume the equilibrium saturation ratio for a solution droplet is a S = 1+- r b p3' then the critical radius is r* = (3b/a)¹/2 and the critical saturation ratio is S* = 1 + [4a³/(276)]¹/2. voming sino
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