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Problem #1 A common gas undergoes equimolar counter-diffusion through a uniform tube 1.55 meters in length. The tube contains air at 101.325 kPa and 298 K. At one point, the partial pressure of the gas is 99.78 kPa and at another point 49.73 kPa. The diffusivity is given as 0.175 x 10-4 m²/s. Calculate the flux for both the gas and air.

Problem #1 A common gas undergoes equimolar counter-diffusion through a uniform tube 1.55 meters in length. The tube contains air at 101.325 kPa and 298 K. At one point, the partial pressure of the gas is 99.78 kPa and at another point 49.73 kPa. The diffusivity is given as 0.175 x 10-4 m²/s. Calculate the flux for both the gas and air.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Problem #1 A common gas undergoes equimolar counter-diffusion through a uniform tube 1.55 meters in length. The tube contains air at 101.325 kPa and 298 K. At one point, the partial pressure of the gas is 99.78 kPa and at another point 49.73 kPa. The diffusivity is given as 0.175 x 10-4 m²/s. Calculate the flux for both the gas and air.
Transcribed Image Text:Problem #1 A common gas undergoes equimolar counter-diffusion through a uniform tube 1.55 meters in length. The tube contains air at 101.325 kPa and 298 K. At one point, the partial pressure of the gas is 99.78 kPa and at another point 49.73 kPa. The diffusivity is given as 0.175 x 10-4 m²/s. Calculate the flux for both the gas and air.
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