Predict the general, or nth term, an, 3, 6, 9, 12, 15, ... O A. 3n OB. +3 OC. n³ O D. 4n of the sequence.

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.2: Arithmetic Sequences And Partial Sums
Problem 1ECP: Write the first four terms of the arithmetic sequence whose nth term is 3n1. Then find the common...
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### Problem: Predict the nth Term of the Sequence

Given the sequence:
\[ 3, 6, 9, 12, 15, \ldots \]

#### Question:
Predict the general, or nth term, \(a_n\) of the sequence.

#### Options:
- A. \( 3n \)
- B. \( n + 3 \)
- C. \( n^3 \)
- D. \( 4n \)

### Analysis:
The sequence given is \(3, 6, 9, 12, 15, \ldots \). Observing the sequence, we can see that each term increases by 3.

#### Steps to Determine the General Term:
1. **Identify the Pattern:**
    - The first term (\(a_1\)) is 3.
    - The second term (\(a_2\)) is 6.
    - The third term (\(a_3\)) is 9.
    - The fourth term (\(a_4\)) is 12.
    - The fifth term (\(a_5\)) is 15.

2. **Calculate the Differences:**
    - \(a_2 - a_1 = 6 - 3 = 3\)
    - \(a_3 - a_2 = 9 - 6 = 3\)
    - \(a_4 - a_3 = 12 - 9 = 3\)
    - \(a_5 - a_4 = 15 - 12 = 3\)

   The common difference is 3, indicating an arithmetic sequence.

3. **Determine the General Term Formula:**
    - For an arithmetic sequence, the nth term can be expressed as:
      \[
      a_n = a_1 + (n-1)d
      \]
      Where \(a_1\) is the first term and \(d\) is the common difference.

4. **Substitute Values:**
    - \(a_1 = 3\)
    - \(d = 3\)

    Therefore,
    \[
    a_n = 3 + (n-1) \cdot 3
    \]
    Simplifying,
    \[
    a_n = 3n
    \]

#### Conclusion:
The general, or nth term, \(a_n\) of the sequence is:
Transcribed Image Text:### Problem: Predict the nth Term of the Sequence Given the sequence: \[ 3, 6, 9, 12, 15, \ldots \] #### Question: Predict the general, or nth term, \(a_n\) of the sequence. #### Options: - A. \( 3n \) - B. \( n + 3 \) - C. \( n^3 \) - D. \( 4n \) ### Analysis: The sequence given is \(3, 6, 9, 12, 15, \ldots \). Observing the sequence, we can see that each term increases by 3. #### Steps to Determine the General Term: 1. **Identify the Pattern:** - The first term (\(a_1\)) is 3. - The second term (\(a_2\)) is 6. - The third term (\(a_3\)) is 9. - The fourth term (\(a_4\)) is 12. - The fifth term (\(a_5\)) is 15. 2. **Calculate the Differences:** - \(a_2 - a_1 = 6 - 3 = 3\) - \(a_3 - a_2 = 9 - 6 = 3\) - \(a_4 - a_3 = 12 - 9 = 3\) - \(a_5 - a_4 = 15 - 12 = 3\) The common difference is 3, indicating an arithmetic sequence. 3. **Determine the General Term Formula:** - For an arithmetic sequence, the nth term can be expressed as: \[ a_n = a_1 + (n-1)d \] Where \(a_1\) is the first term and \(d\) is the common difference. 4. **Substitute Values:** - \(a_1 = 3\) - \(d = 3\) Therefore, \[ a_n = 3 + (n-1) \cdot 3 \] Simplifying, \[ a_n = 3n \] #### Conclusion: The general, or nth term, \(a_n\) of the sequence is:
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