Predict the equilibrium concentration of IBr in the reaction described below (for which Kc = 280 at the reaction temperature) by constructing an ICE table, writing an equilibrium expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-3 before submitting your answer. ₂(g) + Br₂(g) = 2 lBr(g) < PREV 3 NEXT > Based on your ICE table (Part 1), set up the equilibrium expression for Kc in order to determine concentrations of all species. Each reaction participant must be represented by one tile. Do not combine terms. Kc 1 = = 280

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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**Title: Determining Equilibrium Concentrations Using an ICE Table**

**Objective:**
Predict the equilibrium concentration of IBr in the given chemical reaction by constructing an ICE (Initial, Change, Equilibrium) table. Use the expression for \( K_c \) and solve for equilibrium concentrations. Complete Parts 1-3 before submission.

**Chemical Reaction:**
\[ I_2(g) + Br_2(g) \rightleftharpoons 2 \ IBr(g) \]

Given:
- Equilibrium constant, \( K_c = 280 \)

**Instructions:**
1. Use your ICE table from Part 1 to set up the equilibrium expression for \( K_c \).
2. Determine the concentrations of all species at equilibrium.
3. Each reaction participant must be represented by a separate tile. Avoid combining terms.

**Equilibrium Expression Placeholder:**
\[ K_c = \]
\[ \text{(your expression here)} \]
\[ = 280 \]

**Options for Creating the Expression:**
- [x]
- [2x]
- [2x]^2
- [0.400 + x]
- [0.400 + 2x]
- [0.400 - x]
- [0.400 - 2x]
- [0.133 + x]
- [0.133 + 2x]
- [0.133 - x]
- [0.133 - 2x]
- [0.400 + x]^2
- [0.400 + 2x]^2
- [0.400 - x]^2
- [0.400 - 2x]^2
- [0.133 + x]^2
- [0.133 + 2x]^2
- [0.133 - x]^2
- [0.133 - 2x]^2

**RESET Button:**
Use the RESET button to clear your selections and retry as needed.

This educational tool assists in understanding how to represent equilibrium scenarios mathematically and apply concepts of chemical equilibrium using \( K_c \).
Transcribed Image Text:**Title: Determining Equilibrium Concentrations Using an ICE Table** **Objective:** Predict the equilibrium concentration of IBr in the given chemical reaction by constructing an ICE (Initial, Change, Equilibrium) table. Use the expression for \( K_c \) and solve for equilibrium concentrations. Complete Parts 1-3 before submission. **Chemical Reaction:** \[ I_2(g) + Br_2(g) \rightleftharpoons 2 \ IBr(g) \] Given: - Equilibrium constant, \( K_c = 280 \) **Instructions:** 1. Use your ICE table from Part 1 to set up the equilibrium expression for \( K_c \). 2. Determine the concentrations of all species at equilibrium. 3. Each reaction participant must be represented by a separate tile. Avoid combining terms. **Equilibrium Expression Placeholder:** \[ K_c = \] \[ \text{(your expression here)} \] \[ = 280 \] **Options for Creating the Expression:** - [x] - [2x] - [2x]^2 - [0.400 + x] - [0.400 + 2x] - [0.400 - x] - [0.400 - 2x] - [0.133 + x] - [0.133 + 2x] - [0.133 - x] - [0.133 - 2x] - [0.400 + x]^2 - [0.400 + 2x]^2 - [0.400 - x]^2 - [0.400 - 2x]^2 - [0.133 + x]^2 - [0.133 + 2x]^2 - [0.133 - x]^2 - [0.133 - 2x]^2 **RESET Button:** Use the RESET button to clear your selections and retry as needed. This educational tool assists in understanding how to represent equilibrium scenarios mathematically and apply concepts of chemical equilibrium using \( K_c \).
**Predicting Equilibrium Concentration of IBr**

In this task, you'll predict the equilibrium concentration of IBr for the reaction below, with an equilibrium constant \( K_c = 280 \) at the reaction's temperature. Start by constructing an ICE table, writing the equilibrium expression for \( K_c \), and solving for the equilibrium concentration. Complete Parts 1-3 before submitting your answer.

**Reaction:**

\[ \text{I}_2(g) + \text{Br}_2(g) \rightleftharpoons 2 \text{IBr(g)} \]

---

**Instructions:**

In a 3.0 L container at high temperature, 0.400 mol of IBr is introduced to reach equilibrium. Fill in the ICE table with appropriate values to determine the partial pressures of all reactants and products. Use \( x \) variables to represent any unknown change in concentration.

**ICE Table:**

\[
\begin{array}{c|c|c|c}
 & \text{I}_2(g) & \text{Br}_2(g) & 2 \text{IBr(g)} \\\hline
\text{Initial (M)} & & & \\\hline
\text{Change (M)} & & & \\\hline
\text{Equilibrium (M)} & & & \\
\end{array}
\]

---

**Available Inputs:**

- Numerical values are suggested for filling in the ICE table.
- Adjust as necessary to solve for unknowns:
  - \( 0 \)
  - \( 0.400 \)
  - \( 0.133 \)
  - \( +x \)
  - \( +2x \)
  - \( -x \)
  - \( -2x \)
  - Expressions like \( 0.400 + x \), \( 0.400 - 2x \), \( 0.133 - 2x \), etc.

**Note:**

Use the reset option to start over if needed.
Transcribed Image Text:**Predicting Equilibrium Concentration of IBr** In this task, you'll predict the equilibrium concentration of IBr for the reaction below, with an equilibrium constant \( K_c = 280 \) at the reaction's temperature. Start by constructing an ICE table, writing the equilibrium expression for \( K_c \), and solving for the equilibrium concentration. Complete Parts 1-3 before submitting your answer. **Reaction:** \[ \text{I}_2(g) + \text{Br}_2(g) \rightleftharpoons 2 \text{IBr(g)} \] --- **Instructions:** In a 3.0 L container at high temperature, 0.400 mol of IBr is introduced to reach equilibrium. Fill in the ICE table with appropriate values to determine the partial pressures of all reactants and products. Use \( x \) variables to represent any unknown change in concentration. **ICE Table:** \[ \begin{array}{c|c|c|c} & \text{I}_2(g) & \text{Br}_2(g) & 2 \text{IBr(g)} \\\hline \text{Initial (M)} & & & \\\hline \text{Change (M)} & & & \\\hline \text{Equilibrium (M)} & & & \\ \end{array} \] --- **Available Inputs:** - Numerical values are suggested for filling in the ICE table. - Adjust as necessary to solve for unknowns: - \( 0 \) - \( 0.400 \) - \( 0.133 \) - \( +x \) - \( +2x \) - \( -x \) - \( -2x \) - Expressions like \( 0.400 + x \), \( 0.400 - 2x \), \( 0.133 - 2x \), etc. **Note:** Use the reset option to start over if needed.
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