PRACTICE PROBLEM 9.3 two minecarts are connected as shown below. Friction is negligible. ● ● If you know that: ● Minecart 1 mass=8 kilograms Mine cart 1 velocity = 3 m/s to the right Minecart 2 mass=4 kilograms Minecart 2 velocity = 3 m/s to the left Minecart 2 will stick to minecart 1 upon impact via the spring on minecart 2. This spring has a constant (k) =8 N/m ● Minecart 2 is 10 meters away from the wall. Time (t)=0 is when the mine carts collide and stick together. x1 and x2 is the displacement of minecart 1 and 2 respectively from its original position at t=0 Make a second order differential equations system that models the situation and find the solution to the system you make. ● mm ₂ ● Wall 10m
PRACTICE PROBLEM 9.3 two minecarts are connected as shown below. Friction is negligible. ● ● If you know that: ● Minecart 1 mass=8 kilograms Mine cart 1 velocity = 3 m/s to the right Minecart 2 mass=4 kilograms Minecart 2 velocity = 3 m/s to the left Minecart 2 will stick to minecart 1 upon impact via the spring on minecart 2. This spring has a constant (k) =8 N/m ● Minecart 2 is 10 meters away from the wall. Time (t)=0 is when the mine carts collide and stick together. x1 and x2 is the displacement of minecart 1 and 2 respectively from its original position at t=0 Make a second order differential equations system that models the situation and find the solution to the system you make. ● mm ₂ ● Wall 10m
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![PRACTICE PROBLEM 9.3
two minecarts are connected as shown below. Friction
is negligible.
If you know that:
x"
Differential eq:
Minecart 1 mass=8 kilograms
Mine cart 1 velocity = 3 m/s to the right
Minecart 2 mass=4 kilograms
Minecart 2 velocity = 3 m/s to the left
Minecart 2 will stick to minecart 1 upon impact
via the spring on minecart 2. This spring has a
constant (k) =8 N/m
Minecart 2 is 10 meters away from the wall.
Time (t)=0 is when the mine carts collide and
stick together.
x1 and x2 is the displacement of minecart 1 and 2
respectively from its original position at t=0
Make a second order differential equations system that
models the situation and find the solution to the
system you make.
=
x₁(0)
[]
=
Solution:
x₁ (t) =
M
in m₂
I
x₂ (0)
-
Wall
x₁ (0)
10m
x₂ (t)
After the collisions the mine carts will
a. Move closer to the wall
b. Move farther away from the wall
c. Stop moving
x₂ (0)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd61aa0cc-194b-4783-aa03-3c5c9cda5609%2F9ace571d-d5ec-4412-94b7-ec25af7fb9b1%2Fcebo0mz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:PRACTICE PROBLEM 9.3
two minecarts are connected as shown below. Friction
is negligible.
If you know that:
x"
Differential eq:
Minecart 1 mass=8 kilograms
Mine cart 1 velocity = 3 m/s to the right
Minecart 2 mass=4 kilograms
Minecart 2 velocity = 3 m/s to the left
Minecart 2 will stick to minecart 1 upon impact
via the spring on minecart 2. This spring has a
constant (k) =8 N/m
Minecart 2 is 10 meters away from the wall.
Time (t)=0 is when the mine carts collide and
stick together.
x1 and x2 is the displacement of minecart 1 and 2
respectively from its original position at t=0
Make a second order differential equations system that
models the situation and find the solution to the
system you make.
=
x₁(0)
[]
=
Solution:
x₁ (t) =
M
in m₂
I
x₂ (0)
-
Wall
x₁ (0)
10m
x₂ (t)
After the collisions the mine carts will
a. Move closer to the wall
b. Move farther away from the wall
c. Stop moving
x₂ (0)
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