PRACTICE PROBLEM 9.3 two minecarts are connected as shown below. Friction is negligible. ● ● If you know that: ● Minecart 1 mass=8 kilograms Mine cart 1 velocity = 3 m/s to the right Minecart 2 mass=4 kilograms Minecart 2 velocity = 3 m/s to the left Minecart 2 will stick to minecart 1 upon impact via the spring on minecart 2. This spring has a constant (k) =8 N/m ● Minecart 2 is 10 meters away from the wall. Time (t)=0 is when the mine carts collide and stick together. x1 and x2 is the displacement of minecart 1 and 2 respectively from its original position at t=0 Make a second order differential equations system that models the situation and find the solution to the system you make. ● mm ₂ ● Wall 10m

Elements Of Electromagnetics
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PRACTICE PROBLEM 9.3
two minecarts are connected as shown below. Friction
is negligible.
If you know that:
x"
Differential eq:
Minecart 1 mass=8 kilograms
Mine cart 1 velocity = 3 m/s to the right
Minecart 2 mass=4 kilograms
Minecart 2 velocity = 3 m/s to the left
Minecart 2 will stick to minecart 1 upon impact
via the spring on minecart 2. This spring has a
constant (k) =8 N/m
Minecart 2 is 10 meters away from the wall.
Time (t)=0 is when the mine carts collide and
stick together.
x1 and x2 is the displacement of minecart 1 and 2
respectively from its original position at t=0
Make a second order differential equations system that
models the situation and find the solution to the
system you make.
=
x₁(0)
[]
=
Solution:
x₁ (t) =
M
in m₂
I
x₂ (0)
-
Wall
x₁ (0)
10m
x₂ (t)
After the collisions the mine carts will
a. Move closer to the wall
b. Move farther away from the wall
c. Stop moving
x₂ (0)
Transcribed Image Text:PRACTICE PROBLEM 9.3 two minecarts are connected as shown below. Friction is negligible. If you know that: x" Differential eq: Minecart 1 mass=8 kilograms Mine cart 1 velocity = 3 m/s to the right Minecart 2 mass=4 kilograms Minecart 2 velocity = 3 m/s to the left Minecart 2 will stick to minecart 1 upon impact via the spring on minecart 2. This spring has a constant (k) =8 N/m Minecart 2 is 10 meters away from the wall. Time (t)=0 is when the mine carts collide and stick together. x1 and x2 is the displacement of minecart 1 and 2 respectively from its original position at t=0 Make a second order differential equations system that models the situation and find the solution to the system you make. = x₁(0) [] = Solution: x₁ (t) = M in m₂ I x₂ (0) - Wall x₁ (0) 10m x₂ (t) After the collisions the mine carts will a. Move closer to the wall b. Move farther away from the wall c. Stop moving x₂ (0)
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