PRACTICE PROBLEM 9.3 two minecarts are connected as shown below. Friction is negligible. If you know that: Minecart 1 mass=8 kilograms Mine cart 1 velocity = Minecart 2 mass=4 kilograms • Minecart 2 velocity = 3 m/s to the left • mm₂ 3 m/s to the right Minecart 2 will stick to minecart 1 upon impact via the spring on minecart 2. This spring has a constant (k) =8 N/m Minecart 2 is 10 meters away from the wall. • Time (t)=0 is when the mine carts collide and stick together. Differential eq: *=[] x1 and x2 is the displacement of minecart 1 and 2 respectively from its original position at t=0 Solution: 1(t) Make a second order differential equations system that models the situation and find the solution to the system you make. 183 10m x₂(t)

PRACTICE PROBLEM 9.3 two minecarts are connected as shown below. Friction is negligible. If you know that: Minecart 1 mass=8 kilograms Mine cart 1 velocity = Minecart 2 mass=4 kilograms • Minecart 2 velocity = 3 m/s to the left • mm₂ 3 m/s to the right Minecart 2 will stick to minecart 1 upon impact via the spring on minecart 2. This spring has a constant (k) =8 N/m Minecart 2 is 10 meters away from the wall. • Time (t)=0 is when the mine carts collide and stick together. Differential eq: *=[] x1 and x2 is the displacement of minecart 1 and 2 respectively from its original position at t=0 Solution: 1(t) Make a second order differential equations system that models the situation and find the solution to the system you make. 183 10m x₂(t)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Question

PRACTICE PROBLEM 9.3
two minecarts are connected as shown below. Friction is negligible.
If you know that:
Minecart 1 mass=8 kilograms
Mine cart 1 velocity = 3 m/s to the right
Minecart 2 mass=4 kilograms
• Minecart 2 velocity = 3 m/s to the left
MM.
• Minecart 2 will stick to minecart 1 upon impact via the spring on minecart 2.
This spring has a constant (k) =8 N/m
Minecart 2 is 10 meters away from the wall.
Differential eq:
*-[];
=
• Time (t)=0 is when the mine carts collide and stick together.
x1 and x2 is the displacement of minecart 1 and 2 respectively from its
original position at t=0
Solution:
z1(t)
wall.
Make a second order differential equations system that models the situation and
find the solution to the system you make.
10m
x₂(t)
=

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PRACTICE PROBLEM 9.3 two minecarts are connected as shown below. Friction is negligible. If you know that: x" Differential eq: Minecart 1 mass=8 kilograms Mine cart 1 velocity = 3 m/s to the right Minecart 2 mass=4 kilograms Minecart 2 velocity = 3 m/s to the left Minecart 2 will stick to minecart 1 upon impact via the spring on minecart 2. This spring has a constant (k) =8 N/m Minecart 2 is 10 meters away from the wall. Time (t)=0 is when the mine carts collide and stick together. x1 and x2 is the displacement of minecart 1 and 2 respectively from its original position at t=0 Make a second order differential equations system that models the situation and find the solution to the system you make. = x₁(0) [] = Solution: x₁ (t) = M in m₂ I x₂ (0) - Wall x₁ (0) 10m x₂ (t) After the collisions the mine carts will a. Move closer to the wall b. Move farther away from the wall c. Stop moving x₂ (0)
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