• Practice Problem 2: The rate of a reaction CO(g) +3H2(g)→→ CH4(g) + H₂O(g) was determined at 25 °C. From the following data, determine a) the mean reaction order with respect to CO b) the mean reaction order with respect to H₂ c) the overall rate order d) the rate law for the reaction and e) the mean rate constant. Det. [CO] (M) 1 2 3 4 0.100 0.400 0.100 0.400 [H₂] (M) 0.200 0.200 0.600 0.600 Initial rate (M/s) 1.12 x 10-4 4.75 x 10-4 3.45 x 10-4 1.34 x 10-3 Answer: a) x = 1.01 1, b) y = 0.982≈ 1, c) 2, d) rate = k[CO] [H₂], e) k = 5.72 x 10-³M-¹s-¹.
• Practice Problem 2: The rate of a reaction CO(g) +3H2(g)→→ CH4(g) + H₂O(g) was determined at 25 °C. From the following data, determine a) the mean reaction order with respect to CO b) the mean reaction order with respect to H₂ c) the overall rate order d) the rate law for the reaction and e) the mean rate constant. Det. [CO] (M) 1 2 3 4 0.100 0.400 0.100 0.400 [H₂] (M) 0.200 0.200 0.600 0.600 Initial rate (M/s) 1.12 x 10-4 4.75 x 10-4 3.45 x 10-4 1.34 x 10-3 Answer: a) x = 1.01 1, b) y = 0.982≈ 1, c) 2, d) rate = k[CO] [H₂], e) k = 5.72 x 10-³M-¹s-¹.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![the mean time, the rate,
[S₂O3] in the reaction
may label clear outliers
the mean) as such and
e calculation.
on mixtures
NH4)2SO4 (NH4)2S2O8|
(mL)
(mL)
1.50
0.50
1.50
0.50
1.00
1.00
1.00
1.00
following reagents are
um iodide
ium persulfate
m thiosulfate
um nitrate
ium sulfate
odide in the solution in the
Answer: 0.050 M
• Determination of the rate law follows the protocol in ref.
(5). with one difference. A reactant order (rate law
exponent) will be calculated twice using two different
pairs of determinations (e.g. determinations 1 & 2 and
determinations 3 & 4). Then the mean is taken of both
values and reported as order. This is done for each
reactant. This additional step allows us to include more
data and reduce experimental error.
Practice Problem 2: The rate of a reaction
CO(g) +3H₂(g)→ CH4(g) + H₂O(g)
was determined at 25 °C. From the following data,
determine
a) the mean reaction order with respect to CO
b) the mean reaction order with respect to H₂
c) the overall rate order
d) the rate law for the reaction and
e) the mean rate constant.
Det. [CO] (M) [H₂] (M)
1
2
3
4
0.100
0.400
0.100
0.400
0.200
0.200
0.600
0.600
Initial rate (M/s)
1.12 x 10-4
4.75 x 10-4
3.45 x 10-4
1.34 x 10-3
Answer: a) x = 1.01 1, b) y = 0.982 1, c) 2, d)
rate = k[CO] [H₂], e) k = 5.72 x 10-3 M-¹S-¹.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7bc30bfd-54a4-45be-8be6-a7bac17a47af%2F9eee1b94-cb5a-402e-aca4-08570368be8f%2Fovtlqic_processed.jpeg&w=3840&q=75)
Transcribed Image Text:the mean time, the rate,
[S₂O3] in the reaction
may label clear outliers
the mean) as such and
e calculation.
on mixtures
NH4)2SO4 (NH4)2S2O8|
(mL)
(mL)
1.50
0.50
1.50
0.50
1.00
1.00
1.00
1.00
following reagents are
um iodide
ium persulfate
m thiosulfate
um nitrate
ium sulfate
odide in the solution in the
Answer: 0.050 M
• Determination of the rate law follows the protocol in ref.
(5). with one difference. A reactant order (rate law
exponent) will be calculated twice using two different
pairs of determinations (e.g. determinations 1 & 2 and
determinations 3 & 4). Then the mean is taken of both
values and reported as order. This is done for each
reactant. This additional step allows us to include more
data and reduce experimental error.
Practice Problem 2: The rate of a reaction
CO(g) +3H₂(g)→ CH4(g) + H₂O(g)
was determined at 25 °C. From the following data,
determine
a) the mean reaction order with respect to CO
b) the mean reaction order with respect to H₂
c) the overall rate order
d) the rate law for the reaction and
e) the mean rate constant.
Det. [CO] (M) [H₂] (M)
1
2
3
4
0.100
0.400
0.100
0.400
0.200
0.200
0.600
0.600
Initial rate (M/s)
1.12 x 10-4
4.75 x 10-4
3.45 x 10-4
1.34 x 10-3
Answer: a) x = 1.01 1, b) y = 0.982 1, c) 2, d)
rate = k[CO] [H₂], e) k = 5.72 x 10-3 M-¹S-¹.
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