Practice Homework - Module 4 (Momentum) 7 of 13 (> Collision at an Angle Review Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at speed 2v, while the second was traveling at speed v at an angle o south of east (as indicated in the figure). After the collision, the two-car system travels at speed vfinal at an angle 0 east of north. (Figure 1) Part B Express your answer in tems of o. Your answer should contain an inverse trigonometric function using the notation asin, atan etc. and not arcsin, arctan etc. What is the angle 0 with respect to north made by the velocity vector of the two cars after the collision? ♥ View Available Hint(s) Figure 1 of 1 Hint 1. A formula for tan 0 the north-south component. Then Let vfinal x be the east-west component of vfinal, and vfinaly tan 0 Vfinal x Ufinal y Vfinal since the angle asked for is the angle east of north. 2v ΑΣΟ. 19:11 EN 2020-05-04 Pavilio hp HP PavilioD ho f12 prt sc impr. écr. insert f5 fo f2 f3 f4 I01 esc échapp. & $ 3/4 3 P. Vf = + v? – v² sin o Vf = 4-v² sin p Vf = v sin o 4 As for the angle 0: Vfx cos p tan 0 %3D Vfy - sino a. 2- sin o Problem 9.25-copy A 50g ball is launched from ground level at an angle 30° above the borizon Its initial speed is 25 m/s. Pa 19:12 EN 2020-05-04 Pavilion gó hp Poetor eK Parter muco s es 2mVrinal HP Pavilion g series VcosØ त ( हपागर -^ ) VE prt sc inpr. écr. delete uppr esc échapp. Vfx VCOSØ) home debut v? Sing 1v? sin'Ø SinRs 노 pg up P.préc. சன் demity COS²O in?0 up Bd caps lock verr, maj. P.suiv. end fin VE (COs?Ø + Sinz$ )) sin?8)) + VZ - v?5ing ctrd レ2 v?sin® vZSinØ Vt intel Inside CORE 13 indows 7 tan 2. (m PREMIER EXPERIENCE V ca Ø 2. tan オい cO0 coSo Sine tan COSO
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When a light ray (termed as the incident ray) hits a surface and bounces back (forms a reflected ray), the process of reflection of light has taken place.
Sign Convention for Mirrors
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Hello I have a question in regards to b. I have attached the pictures along with my work. Normally, to find an angle it’s arctan (y/x) , but in the answer key they use arctan(x/y) I also don’t understand how they simplify it. Thank you
I have attached, the question, the diagram, my work, and the answer key. My work for part a is correct
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