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Practice: Draw the product for the following reactions (1) NaH a. H-C=C-H (2] CI

Practice: Draw the product for the following reactions (1) NaH a. H-C=C-H (2] CI

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Practice:** Draw the product for the following reactions a. \[ \text{H--C}\equiv\text{C--H} \xrightarrow{[1] \text{NaH}} \quad \text{(arrow pointing to the right)} \quad \xrightarrow{[2] \text{CH}_3CHClCH_3} \] **Explanation:** - Reactant: Acetylene (\(\text{H--C}\equiv\text{C--H}\)) - Reagents: 1. Sodium hydride (NaH) 2. 2-Chloropropane (\(\text{CH}_3CHClCH_3\)) To obtain the final product, students are expected to understand the steps: 1. The acetylene (\(\text{H--C}\equiv\text{C--H}\)) reacts with sodium hydride (NaH). Sodium hydride deprotonates the acetylene, creating an acetylide anion (\(\text{H--C}\equiv\text{C}^- \text{Na}^+ \)). 2. The acetylide anion then reacts with 2-chloropropane (\(\text{CH}_3CHClCH_3\)), where a nucleophilic substitution occurs, resulting in the addition of the substituted propyl group to the acetylene. Students are expected to draw the complete structure of the final organic product synthesized through these two steps. Note: The actual drawing of the resulting product is not included in this transcription and should be illustrated as per the instructor's guidance or additional problem context.
Transcribed Image Text:**Practice:** Draw the product for the following reactions a. \[ \text{H--C}\equiv\text{C--H} \xrightarrow{[1] \text{NaH}} \quad \text{(arrow pointing to the right)} \quad \xrightarrow{[2] \text{CH}_3CHClCH_3} \] **Explanation:** - Reactant: Acetylene (\(\text{H--C}\equiv\text{C--H}\)) - Reagents: 1. Sodium hydride (NaH) 2. 2-Chloropropane (\(\text{CH}_3CHClCH_3\)) To obtain the final product, students are expected to understand the steps: 1. The acetylene (\(\text{H--C}\equiv\text{C--H}\)) reacts with sodium hydride (NaH). Sodium hydride deprotonates the acetylene, creating an acetylide anion (\(\text{H--C}\equiv\text{C}^- \text{Na}^+ \)). 2. The acetylide anion then reacts with 2-chloropropane (\(\text{CH}_3CHClCH_3\)), where a nucleophilic substitution occurs, resulting in the addition of the substituted propyl group to the acetylene. Students are expected to draw the complete structure of the final organic product synthesized through these two steps. Note: The actual drawing of the resulting product is not included in this transcription and should be illustrated as per the instructor's guidance or additional problem context.
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