pounds (operator of the dolly not included). It is known that the board has a maximum load carrying capacity of 242 pounds at its center (weakest point) when horizontal. Round answers to 4 decimal places. Forced pointing down are negative. W2 < 32° = 296 lb a) What is the component of the weight of the dolly perpendicular to the ramp (wi)? 13 13
pounds (operator of the dolly not included). It is known that the board has a maximum load carrying capacity of 242 pounds at its center (weakest point) when horizontal. Round answers to 4 decimal places. Forced pointing down are negative. W2 < 32° = 296 lb a) What is the component of the weight of the dolly perpendicular to the ramp (wi)? 13 13
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![**Title: Understanding Force Components on an Inclined Ramp**
**Image Description:**
In this educational illustration, we analyze a handtruck/dolly being pulled up a board ramp inclined at 32 degrees. The combined weight of the dolly and its load is 296 pounds, excluding the operator. The board can carry a maximum load of 242 pounds at its weakest point when horizontal. All calculations should be rounded to four decimal places. Note: Forces pointing downward are considered negative.
**Diagram Explanation:**
The diagram shows a dolly on a ramp inclined at an angle of 32 degrees. The following components are visualized:
- The total weight vector (\( \vec{w} \)), with a magnitude of 296 lbs, acting vertically downward.
- Two components of the weight vector:
- \( \vec{w}_1 \): perpendicular to the ramp.
- \( \vec{w}_2 \): parallel to the ramp.
- The angle \( \theta \) between the weight vector and its components is shown as 32 degrees.
**Questions:**
a) **What is the component of the weight of the dolly perpendicular to the ramp (\( \vec{w}_1 \))?**
- \( w_1 = \_\_\_\_ \) pounds
b) **What is the component of the weight of the dolly parallel to the ramp (\( \vec{w}_2 \))?**
- \( w_2 = \_\_\_\_ \) pounds
c) **Will the board/ramp break?**
- [ ] Yes
- [ ] No
d) **What force is required to pull the dolly up the ramp?**
- \( \_\_\_\_ \) pounds
This exercise aids in comprehending the forces acting on objects on inclined planes, ensuring safety and efficiency in practical applications.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18608e9e-bffe-4b38-84b4-3b337a037743%2F8867c855-c020-49aa-98d8-8b6f361786d1%2F450dwv7a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Understanding Force Components on an Inclined Ramp**
**Image Description:**
In this educational illustration, we analyze a handtruck/dolly being pulled up a board ramp inclined at 32 degrees. The combined weight of the dolly and its load is 296 pounds, excluding the operator. The board can carry a maximum load of 242 pounds at its weakest point when horizontal. All calculations should be rounded to four decimal places. Note: Forces pointing downward are considered negative.
**Diagram Explanation:**
The diagram shows a dolly on a ramp inclined at an angle of 32 degrees. The following components are visualized:
- The total weight vector (\( \vec{w} \)), with a magnitude of 296 lbs, acting vertically downward.
- Two components of the weight vector:
- \( \vec{w}_1 \): perpendicular to the ramp.
- \( \vec{w}_2 \): parallel to the ramp.
- The angle \( \theta \) between the weight vector and its components is shown as 32 degrees.
**Questions:**
a) **What is the component of the weight of the dolly perpendicular to the ramp (\( \vec{w}_1 \))?**
- \( w_1 = \_\_\_\_ \) pounds
b) **What is the component of the weight of the dolly parallel to the ramp (\( \vec{w}_2 \))?**
- \( w_2 = \_\_\_\_ \) pounds
c) **Will the board/ramp break?**
- [ ] Yes
- [ ] No
d) **What force is required to pull the dolly up the ramp?**
- \( \_\_\_\_ \) pounds
This exercise aids in comprehending the forces acting on objects on inclined planes, ensuring safety and efficiency in practical applications.
Expert Solution
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Component of vector at angle = A cos θ
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