**Problem Statement:****5.** Determine the tensions in the cables.**Diagram Analysis:**The diagram illustrates a system with a weight \(W\) of 500 lbs suspended by two cables. The system is comprised of the following elements:- **Points A, B, and C:** - Point A is the anchoring point of one of the cables, located at a higher elevation. - Point B is the point where both cables meet and support the weight \(W\). - Point C is the anchoring point of the other cable, which is also located at a higher elevation, but 4 feet higher than point B. - **Distances:** - The horizontal distance between point A and point B is given as 6 feet. - The horizontal distance between point B and point C is stated as 5 feet. - Point C is vertically higher than point B by 4 feet.- **Weight:** - The weight \(W\) suspended from the cables at point B is 500 lbs.This setup is typical for solving static equilibrium problems in mechanics, where the goal is to determine the tension forces in each cable supporting the weight.

Given, The horizontal distance from B to A is 6 ft, and that from B to C is 5 ft. The height of A…

Answered: 5. Determine the tensions in the…

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5. Determine the tensions in the cables. A -6 ft- B -50-4 W = 500 lb IC T 4 ft