Chemistry HW. How to answer question 1 and 2？ A full report is required for this labPost lab questions:1. If the precipitate in this experiment was not completely dried at the end of theexperiment, how would that have affected your calculations of the mass percentage?2. In this experiment we are assuming that all of the arsenic in the soil sample reacts. If weadded more than 20 mL of AGNO3, would that have affected your calculations? Pleaseexplain.Z151jofga koalc203c2I1491zduiybeejapytly1ijpng4igvijozanga.pngnash-ngng AsO43+3 Ag+=> AgaAsO4 ()The arsenate is converted into a solid (Ag3AsO4 (s)). If the mass of solid produced is known, wecan calculate the mass percent of arsenic in the 1.00 kg soil sample.Soil Sample 1Volume of soilVolume of 1 MMass of Ag3AsO4 (g)Mass % of As in SoilSample (mL)AGNO: (mL)Sample100.0020.000.370024 g0.006%50.0020.000.185012 g0.003%Soil Sample 2Mass of Ag3AsO4 (g) Mass % of As in SoilSampleVolume of soilVolume of 1 MSample (mL)AGNO3 (mL)20.000.231265 g0.00375%100.0020.000.115633 g0.001875%50.00

The mass percentage of arsenic is calculated in the experiment as:Mass % of arsenic = Molar mass of AsMass of soil sample×Mass of Ag3AsO4 precipitateMolar mass of Ag3AsO4×100If the precipitate obtained is not dried completely and wet mass is recorded, then the calculated mass percentage of Arsenic in soil will be more than the actual mass percentage of arsenic present in the soil sample. The precipitation of arsenic as Ag3AsO4 is given as: AsO43- + 3 Ag+ → Ag3AsO4 (s)If more amount of AgNO3 is added to the solution, then it will not affect the amount of precipitate formed. As, the precipitateobtained is a stoichiometric product based on arsenic content in the sample. So, addition of more than 20 mL of AgNO3 would not affect the calculations of mass percentage of arsenic in soil sample.