populationHeight x P (x)x∙P(x)x2x2 ∙ p(x)54 inches 0.052.72916145.858 inches0.052.93364168.260 inches0.2112.6360075661 inches0.3219.5237211190.7262 inches0.116.823844422.8463 inches0.053.153969198.4564 inches0.053.24096204.866 inches0.053.34356217.867 inches0.117.374489493.79 ∑ p(x)= 1∑ x∙P(x)= 61.56 ∑ x2 ∙ p(x) = 3798.4sampling distribution of the sample Valuesfrequencyprobability162.5 11/35262.7511/3536322/35463.2533/35563.544/35663.7544/3576455/35864.2544/35964.544/351064.7533/35116522/351265.2511/351365.511/35Sum 351activity: Compute for the mean (??̅) and standard deviation (??̅) of the sampling distribution of the samplemeans and compare these to the mean and standard deviation of the population.

We know that, Mean = (summation f*x)/(summation f) And standard deviation= √E(X2)-mean2 E(X2)=…

Answered: population Height x P (x) x∙P(x)…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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population

Height x	P (x)	x∙P(x)	x2	x2 ∙ p(x)
54 inches	0.05	2.7	2916	145.8
58 inches	0.05	2.9	3364	168.2
60 inches	0.21	12.6	3600	756
61 inches	0.32	19.52	3721	1190.72
62 inches	0.11	6.82	3844	422.84
63 inches	0.05	3.15	3969	198.45
64 inches	0.05	3.2	4096	204.8
66 inches	0.05	3.3	4356	217.8
67 inches	0.11	7.37	4489	493.79
	∑ p(x)= 1	∑ x∙P(x)= 61.56		∑ x2 ∙ p(x) = 3798.4

sampling distribution of the sample

	Values	frequency	probability
1	62.5	1	1/35
2	62.75	1	1/35
3	63	2	2/35
4	63.25	3	3/35
5	63.5	4	4/35
6	63.75	4	4/35
7	64	5	5/35
8	64.25	4	4/35
9	64.5	4	4/35
10	64.75	3	3/35
11	65	2	2/35
12	65.25	1	1/35
13	65.5	1	1/35
Sum		35	1

activity:

Compute for the mean (??̅) and standard deviation (??̅) of the sampling distribution of the sample
means and compare these to the mean and standard deviation of the population.

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