ChromeFileEdit ViewHistoryBookmarksProfilesTabWindow Help58% [4)Tue 7:27 PMAnswered: a. For Rite Aid, is th Xf FacebookMindTap - Cengage LearningCengage Learningng.cengage.com/static/nb/ui/evo/index.html?deploymentld=6027871822093185781156284196&elSBN=9780357131596&id=13... ☆CENGAGE MINDTAPQ Search this courseMARY ANGELEEN vProblem Set 4omework Help2.Corey_week 4 assignme3.Kaitlynn Corey Week 4aka4.Consider the following hypothesis test:assignment 1. ConsiderHo: µ = 18A-Z5.following hypothesis teHa: µ # 186.A sample of 40 providea .A sample of 48 provided a sample mean a =17 and a sample standard deviation s = 4.4. Enter negative values as negative numbers.O Officesample mean of 26.4. T7.a. Compute the value of the test statistic (to three decimal places).8.gers Univ BUSINESS 136:287 • 16 views9.b. Use the t distribution table (Table 2 in Appendix B) to compute a range for the p-value (to two decimal places).10.p-value is betweenandС. At a 3:0.05, what is your conclusion?11.p-value isHo.NE ocument- Select your answer -12.d. What is the rejection rule using the critical value?13.EXERCISE FOR HYPOTReject Ho if t is- Select your answer -v or t js- Select your answer -14.EXERCISE FORWhat is your conclusion (to three decimal places)?HYPOTHESIS TESTING15.t =- Select your answer -v Ho.Consider the following16.hypothesis test: HO : µHa: µ > 25 A sample of17.18.0= Icon Keyona State Univ MAT 1150819.20.not processed.pngShow Allboument10KEYNOTENOVPAGES16 A关

We want to find the test statistics and P-value Note: According to bartleby experts question…

Answered: Consider the following hypothesis test:…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following claim (Ha) at a significance level of a = 0.01. H.: µ = 62.4 Ha:H > 62.4 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 31 with mean M 63.6 and a standard deviation of SD = 10.9. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value =
200 people were randomly sampled and asked what they regularly eat for breakfast or lunch. Each person was identified as either a consumer or a non consumer of high-fiber cereals, and the number of calories consumed at lunch was measured and recorded. These data are summarized below; Consumer of high fiber cereals Non consumer of high fiber cereals η1 =41 η2 = 159 Mean 1 =603 Mean 2 =639 Stanadard deviation 1 = 110 Standard deviation 2 = 141 If the scientist claims that people who eat high fiber cereals for breakfast do consume on average fewer calories for lunch than people who don’t eat high fiber cereals for breakfast, and if it is true, high fiber cereal manufacturer will be able to claim another advantage of eating their products-potential weight reduction for dieter. REQUIRED Are there sufficient evidence at 5% significance level to support the above claim?
Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? a. The test statistic, t, is (Round to two decimal places as needed.) b. The P-value is (Round to three decimal places as needed.)
a. Determine the sampling distribution of the sample mean for samples of size 3. Interpret your answer in terms of the distribution of all possible sample mean brain weights for samples of three men. The mean of the sample mean is μx=1.401.40kg. (Type an integer or a decimal. Do not round.) The standard deviation of the sample mean is σx=0.06350.063kg. (Round to four decimal places as needed.) Interpret these answers in context. For samples of three men, the individual brain weights have a normal distribution with a mean of 1.41.4 kg and a standard deviation of 0.06350.0635 kg. (Type integers or decimals rounded to four decimal places as needed.)
Consider the following data for two independent random samples taken from two normal populations. Excel File: data10-11.xlsx Sample 1 10 7 13 7 9 8 Sample 2 8 7 8 4 6 9 a. Compute the two sample means. (to nearest whole number) 9. 7 b. Compute the two sample standard deviations. (to 2 decimals) S1 = 2.28 O 82 = 1.79 O c. What is the point estimate of the difference between the two population means? 2 d. What is the 90% confidence interval estimate of the difference between the two population means? (to 2 decimals and enter negative value as negative number) .05 3.95
Consider the following hypolhesis test: Ho : µ > 240 H. : µ < 240 A sample of 60 provided a sample mean of 234 and a sample standard deviation of 25. Find the value of the test statistic. Select one: O a. t = -1.86 Ob.t = -0.24 O c.t = -2.32 O d. t -0.30
You wish to test the following claim (Ha) at a significance level of a = 0.01. H.:µ = 68.6 Ha:u # 68.6 You believe the population is normally distributed and you know the standard deviation is a= 16.5 .You obtain a sample mean of M = 72.9 for a sample of size n = 25. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = | The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 68.6. O There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 68.6. O The sample data support the claim that the population mean is not equal to 68.6.…
10. For which of the following cases would you use a t-test statistic? A. Where the population distribution is not normal, the population variance is not known and the sample size is below 25. B. Where the population distribution is not normal but the population variance is known. C. Where the population distribution is normal, the population variance is not known and the sample size is below 25. D. Where the population distribution is normal, the population variance is known and the sample size is 25 or more.
Identify the IV and the scale of measurement; Identify the DV and the scale of measurement and for the IV – identify the number of levels; Identify null and alternative hypotheses, are they directional or non-directional? Assume that the distributions of the populations are approximately normal.
3. Use technology and a t-test to test the claim about the population mean μ at the given level of significance α using the given sample statistics. Assume the population is normally distributed. Claim: μ>75; α=0.10 Sample statistics: x=76.4, s=2.9, n=24 a. The standardized test statistic is (Round to two decimal places as needed.) b. What is the P-value of the test statistic? P-value= (Round to three decimal places as needed.) c. Decide whether to reject or fail to reject the null hypothesis. Choose the correct answer below. A. Fail to reject H0. There is not enough evidence to support the claim. B. Reject H0. There is enough evidence to support the claim. C. Fail to reject H0. There is enough evidence to support the claim. D. Reject H0. There is not enough evidence to support the claim.
Consider the following sample: 10 22 63 70 98 the mean and sample standard deviation of which are 52.6000 and 36.1359.What is the z-score of '10'? (Leave your answer to 2 decimals: ex: 1.23)
These are the numbers I am working with: Sample mean= 78 Population mean= 75 Standard deviation:=10 Significance level: .05 Critical value: Z score > 1.96 Z score= 1.34 How do I figure the confidence limits for the 95% confidence interval. Z-score= 1.34 P-value= .1802

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