One line of specialty tires has a wear-out life that can be modelled using Normal distribution with a mean of 25,000 km and a standard deviation of 2,000 km. Determine each of the following: a. The percentage of tires that can be expected to wear out within ± 2,000 km of the average (i.e., between 23,000 km and 27,000 km). b. The percentage of tires that can be expected to fail between 26,000 km and 29,000 km. c. For what tire life would you expect 4 percent of the tires to have worn out?

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A: simplified value is -24.44 v - 17.3

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A: Given that,A=-9-411 and B=-6-829.   Obtain A·B as follows. A·B=-9-411-6-829      =-9-6-4-8+12+49…

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Q: so what are the values of d and c?

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